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Tom [10]
3 years ago
5

I'm studying for a quiz but I don't know how to do these two questions! Can someone explain them to me?

Mathematics
2 answers:
marissa [1.9K]3 years ago
3 0

hope u can understand mate..if u have any queries please contact me..thx

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EastWind [94]3 years ago
3 0

Answer:

11. m∠ABD = 28°

Other Q. m∠1 = 61°

Step-by-step explanation:

11) Extend line BE. Because of the Alternate Interior Angles Theorem, ∠ABE is congruent to ∠BEF. m∠BEF = 118°, so m∠ABD + m∠DBE = 118°. Because ∠DBE is a right angle, it equals 90°. So m∠ABD + 90° = 118°. So m∠ABD = 28.

Other Q.) Looking only at line <em>a</em>, line <em>b</em>, and the line next to angle 3 and angle 1. ∠3 is congruent to ∠1 + 74° by the Corresponding Angles Theorem. Now, we have:

m∠3 = m∠1 + 74°

So we have to find the measure of angle 3.

Angle 3 is supplementary to 45°, meaning their sum is 180°, because they're linear pairs.

180 - 45 = m∠3

              = 135°

Now, plug in the values to the previous:

m∠3 = m∠1 + 74°

135° = m∠1 + 74°

m∠1 = 135 - 74

        = 61°

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Natalija [7]
2a.
Since BC = 10m and M is the midpoint, we can find CM by : 10÷2 = 5m
So, CM = 5m

2b. Now, you have the base ( 5m) & hypotenuse (13m). Pythagoras' Theorem:

c {}^{2}  =  {a}^{2}  +  {b}^{2}
Where c is the hypotenuse, a & b are sides.

{13}^{2}  =  {5}^{2}  + b {}^{2}  \\  {5}^{2}  +  {b}^{2}  = 13 {}^{2}  \\  {b}^{2}  = 13 {}^{2}  -  {5}^{2}  \\ b =  \sqrt{144}  \\ b = 12
b here refers to the height.

2c.
Area of a right-angled triangle =
\frac{base \times height}{2}
So,
\frac{10 \times 12}{2} \\  = 60 {m}^{2}
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