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adelina 88 [10]
3 years ago
5

What is the area of the shaded segment?

Mathematics
1 answer:
Whitepunk [10]3 years ago
8 0

Answer:

6\pi-9\sqrt{3

Step-by-step explanation:

The area of a pie-slice shape can be found with the equation A=\pi nr^2/360 where n is the angle of the shape and r is the radius of the circle. In this case, n=60 and r=6. Therefore, the total area of the pie-slice is \pi (60)(6^2)/360=6 \pi

Next, the triangle that makes up the unshaded part of the segment is an equilateral triangle because the angle is 60. The area of an equilateral triangle is \sqrt{3}r^2/4 where r is the length of one of its side (in this case, r=6). Plugging that in, we get an area of 9 \sqrt{3}

Finally, the area of the shaded is the area of the pie-slice minus the area of the triangle: 6\pi-9\sqrt{3

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--110 = -2(8x + 7)<br> A) {6} B) (16)<br> C) (9) D) (14)
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What is the greatest value in the range of f(x) = x^2 - 3 for the domain (-3,0,1,2)
bezimeni [28]

Answer:

f(-3)=6 is the greatest value in the range of f(x)=x^2-3 for the domain (-3,0,1,2)

Step-by-step explanation:

Given that the function f is defined for range by f(x)=x^2-3 for the domain (-3,0,1,2)

To find the greatest value in the range of f(x)=x^2-3 for the domain (-3,0,1,2):

f(x)=x^2-3 for the domain (-3,0,1,2)

That is put x=-3 in the given function f(x)=x^2-3 we get

f(-3)=(-3)^2-3

=3^2-3

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=6

Therefore f(-3)=6

put x=0 in the given function f(x)=x^2-3 we get

f(0)=(0)^2-3

=0-3

=-3

Therefore f(0)=-3

put x=1 in the given function f(x)=x^2-3 we get

f(1)=(1)^2-3

=1-3

=-2

Therefore f(1)=-2

put x=-3 in the given function f(x)=x^2-3 we get

f(2)=(2)^2-3

=4-3

=1

Therefore f(2)=1

Comparing the values of f(-3)=6,f(0)=-3,f(1)=-2,and f(2)=1 to find the greatest value in the range of f(x) = x^2 - 3 for the domain (-3,0,1,2) we get

Therefore f(-3)=6 is the greatest value in the range of f(x)=x^2-3 for the domain (-3,0,1,2)

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3 years ago
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