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Verdich [7]
3 years ago
6

2. The table shows a function. x 0 1 2 3 5 13 21 29 37 45 53 (a) Is the function linear, exponential, or neither? (b) What is th

e pattern that you observe in the table? (for example: adding 5 each time x increases by 1, dividing by 2 each time x increases by 3) If there is no pattern, show that there is no pattern. (c) What is the y-intercept of the function represented by the table? (be sure to write as an ordered pair)
Mathematics
1 answer:
Pavlova-9 [17]3 years ago
8 0

Solution:

The Ordered pair of the function is

x :  0      1     2   3     4   5

y:   13  21  29  37  45   53  

(a)  \frac{\text{Change in y values}}{\text{Change in x values}}=\frac{21-13}{1-0}=\frac{29-21}{2-1}=\frac{37-29}{3-2}=\frac{45-37}{4-3}=\frac{53-45}{5-4}=8

Slope between two points are same.So,the function Represented in terms of ordered pairs Linear.

(b) As, you can each Successor of x values is obtained by adding 1 to it's Predecessor.

and , each Successor of y values is obtained by adding 8 to it's Predecessor.

(c) Taking any two ordered pairs , (0,13) and (1,21) we can find an equation of line passing through these 5 points (2,29),(3,37),(4,45),(5,53)

Equation of line passing through passing through two points (x_{1},y_{1}),{\text and} (x_{2},y_{2}) is given by

 = \frac{y-y_{1}}{x-x_{1}}=\frac{y_{2}-y_{1}}{x_{2}-x_{1}}

= \frac{y-13}{x-0}=\frac{21-13}{1-0}

→ y -13 = 8 x

→ y = 8 x + 13

So, Y intercept = 13

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around a square with diagonal d = 4.6 cm a circle is described. Calculate the perimeter of the circle​
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Answer:

14.45cm2

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Theorem: The segment joining the midpoints of two sides of a triangle is parallel to the third side and half its length. A two-c
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Answer:  By the slope formula.

Step-by-step explanation:

Given: ABC is a triangle (shown below),

In which A≡(6,8), B≡(2,2) and C≡(8,4)

And, D and E are the mid points of the line segments AB and BC respectively.

Prove: DE║AC and DE = AC/2

Proof:

Since, And, D and E are the mid points of the line segments AB and BC respectively.

Therefore, By mid point theorem,

coordinate of D are (\frac{2+6}{2} , \frac{2+8}{2} ) = (\frac{8}{2} , \frac{10}{2} )= (4,5)

Coordinate of E are  (\frac{2+8}{2} , \frac{2+4}{2} ) = (\frac{10}{2} , \frac{6}{2} )= (5,3)

By the distance formula,

DE=\sqrt{(5-4)^2+(3-5)^2}=\sqrt{5}

AC=\sqrt{(8-6)^2+(4-8)^2}=2\sqrt{5}

By the slope formula,

Slope of AC = \frac{4-8}{8-6} = \frac{-4}{2} = -2

Slope of DE =  \frac{3-5}{5-4} = \frac{-2}{1} = -2


            Statement                                              Reason

1. The coordinate of D are (4,5)  and           1. By the midpoint formula

the coordinate of  E are (5,3)

2. The length of DE = √5                            2. By the Distance formula

The length AC = 2√5 ⇒ Segment DE

is half the length of segment AC

3. The slope of DE = -2 and the                3. By the slope formula

slope of AC = -2

4. DE║AC                                                   4. Slopes of parallel lines are equal


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