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abruzzese [7]
3 years ago
12

What is the ratio in simplest form between the length of a side in MARDT and the length of its corresponding side in JPLSF?

Mathematics
1 answer:
melomori [17]3 years ago
5 0

Answer:

Look I am looking for the answer to this question.....So I'm guessing that the answer is B 4/3

Step-by-step explanation:

Correct me if I'm wrong :)

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Can predictions be made of a scatterplot that shows no association? explain your answer.
hichkok12 [17]
<span>No, you can't make a prediction from a scatter plot that doesn't show any associations. There have to be associations in order to form a trend. If there is no trend, there is no way to make a prediction. A scatter plot is similar to a line graph where you can mark the appropriate data points in order to see if a trend is developing.</span>
3 0
3 years ago
Read 2 more answers
A boy has 380 prize tickets he wants to exchange for action figures at a prize booth. At
loris [4]

Answer:

Step-by-step explanation:

 

Hi there,

If the boy wants 80 small action figures

that is equivalent to 40 x 7 (as 7 tickets

gives him 2 small action figures)

= 280 tickets.

The 380 tickets he has originally minus the

280 leaves 100 tickets to get 20 large action figures

(100/5)

He will have 80 small and 20 large action figures

80:20 = 4:1

Hope this helps:-)

6 0
3 years ago
What is the 1st term when −5z2 + 7z4 + 11z − 8z3 is arranged in descending order
patriot [66]
Descending order...largest to smallest
the largest one is the one with the biggest exponent
so the first term is : 7z^4
3 0
3 years ago
Read 2 more answers
Dalton's dad rode his bike 1 kilometer north,1 kilometer west,1 kilometer south,and 2 kilometer east.How many total kilometers w
Georgia [21]
1 + 1 + 1 + 2 = 5

5 x 9 = 45

Therefore, the total number of km is 45.
3 0
3 years ago
<img src="https://tex.z-dn.net/?f=%28%20%5Csin%5E%7B2%7D%20%28%20%5Cfrac%7B%5Cpi%7D%7B%204%20%7D%20%20-%20%20%5Calpha%20%29%20%2
guapka [62]

Step-by-step explanation:

\sin^2 (\frac{\pi}{4} - \alpha) = \frac{1}{2}(1 - \sin 2\alpha)

Use the identity

\sin^2 \theta = \dfrac{1 - \cos 2\theta}{2}

on the left side.

\dfrac{1 - \cos [2(\frac{\pi}{4} - \alpha)]}{2} = \frac{1}{2}(1 - \sin 2\alpha)

\dfrac{1 - \cos (\frac{\pi}{2} - 2\alpha)}{2} = \frac{1}{2}(1 - \sin 2\alpha)

Now use the identity

\sin \theta = \cos(\frac{\pi}{2} - \theta)

on the left side.

\dfrac{1 - \sin 2\alpha}{2} = \frac{1}{2}(1 - \sin 2\alpha)

\frac{1}{2}(1 - \sin 2\alpha) = \frac{1}{2}(1 - \sin 2\alpha)

4 0
2 years ago
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