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vfiekz [6]
3 years ago
10

Greatest common factor of 8 and 32.

Mathematics
2 answers:
Zinaida [17]3 years ago
8 0

Answer:

8, 4, 2, 1

Step-by-step explanation:

DENIUS [597]3 years ago
6 0

Answer:

8

Step-by-step explanation:

The GCF is the biggest number that can be multiplied into both numbers, it can't go above 8 because nothing higher than 8 will be able to be multiplied to 8

8 x 1 = 8

8 x 4 = 32

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Consider F and C below. F(x, y) = x4y5i + x5y4j, C: r(t) = t3 − 2t, t3 + 2t , 0 ≤ t ≤ 1 (a) Find a function f such that F = ∇f.
vovikov84 [41]
\mathbf f(x,y)=x^4y^5\,\mathbf i+x^5y^4\,\mathbf j

We want a scalar function f(x,y) whose gradient is equivalent to the vector field. That means

\dfrac{\partial f}{\partial x}=x^4y^5\implies f(x,y)=\dfrac{x^5y^5}5+g(y)
\dfrac{\partial f}{\partial y}=x^5y^4\implies x^5y^4=x^5y^4+\dfrac{\mathrm dg}{\mathrm dy}
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So (a)

f(x,y)=\dfrac{x^5y^5}5+C

which means (b)

\displaystyle\int_{\mathcal C}\mathbf f\cdot\mathrm d\mathbf r=f(\mathbf r(1))-f(\mathbf r(0))=f(-1,3)-f(0,0)=-\dfrac{243}5-0=-\dfrac{243}5
5 0
3 years ago
Find the greatest common factor of the following monomials 34n^5 32n4
Andrew [12]

Answer:

by u meant 32n^4, then the answer is 2n^4

Step-by-step explanation:

first find the gcf of the coefficient

32 and 34

their gcf is 2, because they're both even but have no other common factor, so it is 2

then for the variables

n^4 and n^5

their gcf is n^4. you can tell by dividing each term by n^4

n^4 / n^ 4 = 1

n^5 / n^4 = n

so then 2 * n^4 is 2n^4

7 0
3 years ago
Read 2 more answers
Hey guys! Sorry to bother but I need help with these. 5th grade math, will give brainliest! (If you see multiple questions by me
ad-work [718]

Answer:

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Step-by-step explanation:

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2 years ago
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olga nikolaevna [1]

The decimal form for 5.63 x 10^-6 is 0.00000563

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3 years ago
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Lelechka [254]
<span>This is the equation made from the problem where x=mystery number
</span><span>2x+3(x+1)=4(x-1)</span><span>

</span><span>Now let's solve for x!
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</span><span>subtract 3 form both sides
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3 years ago
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