Answer:
The answer is Graph X.
- Always start by isolating the variable \color{red}y on the left side of the inequality.
- Change the inequality to equality symbol.
- Graph the boundary line from step 2 in the XY-plane.
- The last step is to shade one side or region of the boundary line.
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Answer: The correct option is second.
Explanation:
The given function is,

If we graph a function is f(x), then its coordinates is defined as (x,f(x)).
When the graph of f(x) is reflect across the x-axis, then the the x-coordinate remains the same and the sign of y-coordinate is changed. It means after reflecting across the x-axis,

The given given equation can be written as,

To find the equation of the graph after reflection across the x-axis multiply both sides by -1.

Because f(x)=y and g(x)=-y.

Therefore the second option is correct and the graph of both function is given below.
23958
23598
25938
25398
29538
29358
here they all are
Answer:
u trrahs at fritnote
Step-by-step explanation:
Answer:

Step-by-step explanation:

[pay attention to the signs :)
