Since we know a circle has 360 degrees, the sector bounded by a 90 degree arc will be a quarter of circle (360/90 = 4). Then, to calculate the area of that sector, we can calculate the total area of the circle of radius 10, and then divide it by 4.
The area of a cirlce of radius r is:
Then, the area of the sector would be:
NOT NECESSARILY would a triangle be equilateral if one of its angles is 60 degrees. To be an equilateral triangle (a triangle in which all 3 sides have the same length), all 3 angles of the triangle would have to be 60°-angles; however, the triangle could be a 30°-60°-90° right triangle in which the side opposite the 30 degree angle is one-half as long as the hypotenuse, and the length of the side opposite the 60 degree angle is √3/2 as long as the hypotenuse. Another of possibly many examples would be a triangle with angles of 60°, 40°, and 80° which has opposite sides of lengths 2, 1.4845 (rounded to 4 decimal places), and 2.2743 (rounded to 4 decimal places), respectively, the last two of which were determined by using the Law of Sines: "In any triangle ABC, having sides of length a, b, and c, the following relationships are true: a/sin A = b/sin B = c/sin C."¹
Proportion if im not mistaken
is over of percent over 100
14 over 168 and x over 100 . 14 times 100 divided b 168 i believe .
The rational is
product 3.12x1.4, √9x√25, sum 4+5 and product nx3.
Good luck!!!
1. The monomial, x, a factor of the expression x2 + 15x "represents the side length, in centimeters, of the photo." So Choice A.
2. The binomial, (x + 15), a factor of the expression x2 + 15x is Choice D because x is the length of the photo plus the 15 cm left of the frame.
3. The first-degree term of the expression x2 + 15x is the area of the photo since "x" is the length. So, Choice C.
4. The second-degree term of the expression x2 + 15x is the area of the frame around the picture. That leaves us with Choice B.
