3 years ago

I need help on number30) -9a=-27

Mathematics

1 answer:

kvasek [131]3 years ago

7 0

A= 3 Why?

Hope this help you boo

You might be interested in

using the midpoint formula, solve for the midpoint of the segment with these pairs of endpoints (-11,30) and (-26,-2)

REY [17]

Answer:

Midpoint is $(\frac{-37 }{2}, 14)$

Step-by-step explanation:

Midpoint = $(\frac{x_{1} + x_{2} }{2}, \frac{y_{1} + y_{2} }{2})$

= $(\frac{-11 -26}{2}, \frac{30 - 2 }{2})$

= $(\frac{-37 }{2}, \frac{28 }{2})$

= $(\frac{-37 }{2}, 14)$

Midpoint is (-37/2, 14)

3 0

3 years ago

The mean amount purchased by a typical customer at Churchill’s Grocery Store is $23.50, with a standard deviation of $5.00. Assu

m_a_m_a [10]

Answer: 0.0170

Step-by-step explanation:

Given : The mean amount purchased by a typical customer at Churchill’s Grocery Store is $23.50, with a standard deviation of $5.00.

i.e. $\mu=23.50$

$\sigma=5$

We assume the distribution of amounts purchased follows the normal distribution.

Sample size : n=50

Let $\overline{x}$ be the sample mean.

Formula : $z=\dfrac{\overline{x}-\mu}{\dfrac{\sigma}{\sqrt{n}}}$

Then, the probability that the sample mean is at least $25.00 will be :-

$P(\overline{x}\geq\25.00)=P(\dfrac{\overline{x}-\mu}{\dfrac{\sigma}{\sqrt{n}}}\geq\dfrac{25-23.50}{\dfrac{5}{\sqrt{50}}})\\\\=P(z\geq2.12)\\\\=1-P(z$

Hence, the likelihood the sample mean is at least $25.00= 0.0170

5 0

3 years ago

Is the following shape a square? How do you know

DENIUS [597]

No, because all sides are not congruent. The answer is B.

5 0

3 years ago

Read 2 more answers

the probability of winning a game is 20%. if you play 20 times how many times should you expect to win

julia-pushkina [17]

The probability of winning a game out of 20 is 4 times.

6 0

3 years ago

Read 2 more answers

I dont know any of this and i was absent so i dont know anything. PLEASE HELP

Elina [12.6K]

It's pretty simple if you just read through it carefully. Here you go.

6 0

2 years ago