Answer:
The time interval when 
is at 
The distance is 106.109 m
Step-by-step explanation:
The velocity of the second particle Q moving along the x-axis is :
So ; the objective here is to find the time interval and the distance traveled by particle Q during the time interval.
We are also to that :
between 
The schematic free body graphical representation of the above illustration was attached in the file below and the point when is at 4 is obtained in the parabolic curve.
So, is at
Taking the integral of the time interval in order to determine the distance; we have:
distance = 
= 
= By using the Scientific calculator notation;
distance = 106.109 m
Answer:
y+4=-3(x+0) or y=-3x-4
Step-by-step explanation:
so you have to make it in form y=mx+b
that would be y=1/3x-2/3
for a perpendicular line, you would need to find the opposite reciprocal of the slope
3/1 or 3 would be the reciprocal, so to make it opposite would be -3
So it would be y-y1 = m(x-x2)
fill it in with the coordinates (0,-4)
y+4=-3(x-0)
to get it to slope intercept form you have to simplify, and after that you get y=-3x-4
Answer:
x = 19
Step-by-step explanation:
148 and 7x+15 are alternate interior angles and alternate interior angles are equal when the lines are parallel
148 = 7x+15
Subtract 15 from each side
148-15 = 7x+15-15
133 =7x
Divide each side by 7
133/7 =7x/7
19=x
9 hope this is right 65% accurate answer
Answer:
10 units
Step-by-step explanation:
