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Lana71 [14]
2 years ago
15

Can you slove any one question ​

Mathematics
2 answers:
kherson [118]2 years ago
5 0

Answer:

Step-by-step explanation:

I'm not sure how to solve the first one, but I'll try to simplify sqrt3-1/sqrt3+1. I simplified it and I got 2-sqrt3. Does that help?

For question 2, I got -0.251.

SVEN [57.7K]2 years ago
3 0

Answer:

1) \frac{\sqrt{3}-1 }{\sqrt{3}+1}=\frac{(\sqrt{3}-1)^{2}  }{(\sqrt{3}+1)(\sqrt{3}-1)  }=\frac{4-2\sqrt{3} }{3-1}=\frac{4-2\sqrt{3} }{2}=2-\sqrt{3}

but \frac{\sqrt{3}-1 }{\sqrt{3}+1 }=a+b\sqrt{3}

=> a = 2

    b = -1

2) \frac{\sqrt{10}-\sqrt{15}  }{2\sqrt{2} }=\frac{\sqrt{20}-\sqrt{30}  }{4}=\frac{2\sqrt{5}-\sqrt{30}  }{4}=-0.251

Step-by-step explanation:

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What does 2(5*-3) =
ladessa [460]

Answer:

-30

Step-by-step explanation:

<u>Step 1:  Multiply inside the parenthesis </u>

2(5 * -3)

2(-15)

<u>Step 2:  Multiply </u>

<u />2(-15)

2 * -15

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Answer:  -30

7 0
3 years ago
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Step-by-step explanation:

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2 years ago
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Step-by-step explanation:

7 0
2 years ago
X - y = 2<br> 4x – 3y = 11
swat32

Answer:

<u><em>For x - y = 2</em></u>

You need to find x or y in one of the equations and then substitute that into the other.

So we have;

x-y=2

4x-3y=11

We will take the first equation and find x;

x-y=2

add y to both sides;

x-y+y=2+y

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Now we take that answer and substitute it forx in the other equation;

 

4(2+y)-3y=11

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Now we have what y equals, so we use it in the first equation to find x;

x-3=2

x=5

So we have;

x=5; y=3

Hope you understand!

=)

<u><em>And for 4x – 3y = 11</em></u>

Multiply the first equation by 2 and the second by 3 so that there are the same number of y's in each:

8x - 6y = 22    ...(3)

30x + 6y = -3  ...(4)

 Now add (3) and (4) term by term:

38x + 0 = 19

or

38x = 19

or x = 1/2

Put this back into equation (1)

4*(1/2) - 3y = 11

or

2 - 3y = 11

Subtract 2 from both sides:

-3y = 9

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6 0
3 years ago
Read 2 more answers
What is 4×5/8 please write the correct answer
wel
The answer would be 2.5.

hope this helps (;

4 0
3 years ago
Read 2 more answers
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