300/L . Just divide area by one side
Answer:
The probability that an athlete chosen is either a football player or a basketball player is 56%.
Step-by-step explanation:
Let the athletes which are Football player be 'A'
Let the athletes which are Basket ball player be 'B'
Given:
Football players (A) = 13%
Basketball players (B) = 52%
Both football and basket ball players = 9%
We need to find probability that an athlete chosen is either a football player or a basketball player.
Solution:
The probability that athlete is a football player = 
The probability that athlete is a basketball player = 
The probability that athlete is both basket ball player and football player = 
We have to find the probability that an athlete chosen is either a football player or a basketball player
.
Now we know that;

Hence The probability that an athlete chosen is either a football player or a basketball player is 56%.
Answer:
The measurement for "A" is 1.5
Answer:
The answer is = −70s+63
Step-by-step explanation:
7(1−10s+8)
=(7)(1+−10s+8)
=(7)(1)+(7)(−10s)+(7)(8)
=7−70s+56
=−70s+63