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2 years ago

Please answer correctly !!!!! Will mark brainliest !!!!!!!!!!!!

Mathematics

1 answer:

Zarrin [17]2 years ago

5 0

Answer:

Up by 3 units, right by 9 units.

Step-by-step explanation:

The subtraction in (x-9)^2 makes the function shift to the right, adding would make it shift left! Adding numbers to the equation would make the function go up, and subtracting would make it go down. Hope this helps :)

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Is the following relation a function? (

PolarNik [594]

No, because there are TWO values of y for a certain value of x

say x=5, then y=2 and y=-2

That does not satisfy the concept of the function.

4 0

3 years ago

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Help ASAP due in 10 mins!!

sladkih [1.3K]

Answer:

im guessing it is 48, -96

Step-by-step explanation:

going by the waves ;/

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3 years ago

What is the solution to this equation y=4x (1,3) (-1,-4) (-4,-1) (1,-4) !ASAP!

RideAnS [48]

(-1,-4) this is saying that when x=-1, y=-4. Plugging it into the line equation y=4x gives
$(- 4) = 4( - 1)$
Which is correct.

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2 years ago

If DH = 4x – 10 and FH = x + 8, find the value of x for which DEFG must be a parallelogram

Zanzabum

I think it is a rectangle..........But i'm not sure what are your options

6 0

3 years ago

Read 2 more answers

Evaluate the series

dalvyx [7]

Answer:

the value of the series;

$\sum_{k=1}^{6}(25-k^2) = 59$

C) 59

Step-by-step explanation:

Recall that;

$\sum_{1}^{n}a_n = a_1+a_2+...+a_n\\$

Therefore, we can evaluate the series;

$\sum_{k=1}^{6}(25-k^2)$

by summing the values of the series within that interval.

the values of the series are evaluated by substituting the corresponding values of k into the equation.

$\sum_{k=1}^{6}(25-k^2) =(25-1^2)+(25-2^2)+(25-3^2)+(25-4^2)+(25-5^2)+(25-6^2)\\\sum_{k=1}^{6}(25-k^2) =(25-1)+(25-4)+(25-9)+(25-16)+(25-25)+(25-36)\\\sum_{k=1}^{6}(25-k^2) =24+21+16+9+0+(-11)\\\sum_{k=1}^{6}(25-k^2) = 59\\$

So, the value of the series;

$\sum_{k=1}^{6}(25-k^2) = 59$

6 0

3 years ago