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2 years ago

10

What is 78902 times 6743 divided by 567.

2 answers:

Agata [3.3K]2 years ago

7 0

Answer:

938,347.3

Step-by-step explanation:

78,903 x 6,743 = 532,042,929‬

532,042,929 ÷ 567 = 938,347.3174603175‬

938,347.3174603175 can be rounded to the nearest tenth. This results in 938,347.3.

bearhunter [10]2 years ago

3 0

Answer:

938335.425044

Step-by-step explanation:

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3 years ago

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Disregarding wind resistance the distance a body falls from rest varies directly as th squares of the time it falls if a skydive

Firdavs [7]

Answer:

The skydiver will fall 1600 ft in 10 seconds.

Step-by-step explanation:

<u>Distance a body falls from rest varies directly as the squares of the time it falls </u>

Let distance = s

time = t

Therefore , s = k $\times t^{2}$

Given, the body falls 64 ft in 2 seconds.

Substituting in above equation,

64 = k $\times (2)^{2}$

64 = k $\times (4)$

k = $\frac{64}{4}$

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We have to find how much he will fall in 10 seconds.

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3 0

3 years ago

1. S(–4, –4), P(4, –2), A(6, 6) and Z(–2, 4) a) Apply the distance formula for each side to determine whether SPAZ is equilatera

Aleksandr [31]

Answer:

a) SPAZ is equilateral.

b) Diagonals SA and PZ are perpendicular to each other.

c) Diagonals SA and PZ bisect each other.

Step-by-step explanation:

At first we form the triangle with the help of a graphing tool and whose result is attached below. It seems to be a paralellogram.

a) If figure is equilateral, then SP = PA = AZ = ZS:

$SP = \sqrt{[4-(-4)]^{2}+[(-2)-(-4)]^{2}}$

$SP \approx 8.246$

$PA = \sqrt{(6-4)^{2}+[6-(-2)]^{2}}$

$PA \approx 8.246$

$AZ =\sqrt{(-2-6)^{2}+(4-6)^{2}}$

$AZ \approx 8.246$

$ZS = \sqrt{[-4-(-2)]^{2}+(-4-4)^{2}}$

$ZS \approx 8.246$

Therefore, SPAZ is equilateral.

b) We use the slope formula to determine the inclination of diagonals SA and PZ:

$m_{SA} = \frac{6-(-4)}{6-(-4)}$

$m_{SA} = 1$

$m_{PZ} = \frac{4-(-2)}{-2-4}$

$m_{PZ} = -1$

Since $m_{SA}\cdot m_{PZ} = -1$ , diagonals SA and PZ are perpendicular to each other.

c) The diagonals bisect each other if and only if both have the same midpoint. Now we proceed to determine the midpoints of each diagonal:

$M_{SA} = \frac{1}{2}\cdot S(x,y) + \frac{1}{2}\cdot A(x,y)$

$M_{SA} = \frac{1}{2}\cdot (-4,-4)+\frac{1}{2}\cdot (6,6)$

$M_{SA} = (-2,-2)+(3,3)$

$M_{SA} = (1,1)$

$M_{PZ} = \frac{1}{2}\cdot P(x,y) + \frac{1}{2}\cdot Z(x,y)$

$M_{PZ} = \frac{1}{2}\cdot (4,-2)+\frac{1}{2}\cdot (-2,4)$

$M_{PZ} = (2,-1)+(-1,2)$

$M_{PZ} = (1,1)$

Then, the diagonals SA and PZ bisect each other.

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2 years ago

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3 years ago

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Answer:

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Step-by-step explanation:

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3 years ago