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3 years ago

7

Can someone help me!?!?

1 answer:

amm18123 years ago

5 0

It's the first step.4x-x-2+6=6x+16 ##substract 2 rather an add 2

Check it carefully next time.!!

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3 years ago

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3 years ago

HELP! A semi circle of radius 6 is centered at the origin as shown. A rectangle has two of its vertices at (5,0) and (-5,0) and

Ugo [173]

The Area of rectangle is " $30 \ unit^2$ " and the equation of the semi circle is " $y = \sqrt{36-x^2}$ ".

According to the question,

The vertices of rectangle,

(5, 0) and (-5, 0)

Length,

l = 10 unit

Breadth,

b = 3 unit

Radius of semi circle,

r = 6

Centre of origin,

(0, 0)

As we know,

→ The Area of rectangle is:

= $Length\times Breadth$

= $10\times 3$

= $30 \ unit^2$

and,

→ The Equation of semi circle is,

$y = \sqrt{r^2-x^2}$

by substituting the values, we get

$=\sqrt{(6)^2-x^2}$

$= \sqrt{36-x^2}$

Thus the above is the correct answers.

Learn more about Area of rectangle here:

brainly.com/question/14383947

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3 years ago