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RideAnS [48]
3 years ago
12

Please just a quick question can, can you help me. The length of a rectangle is 8cm longer than its breadth, If the perimeter of

the rectangle is 80 cm, find its length and breadth * choose one of the options 1.length = 16cm and breadth = 64cm 2.length = 16cm and breadth = 22cm 3.length = 24cm and breadth = 64cm 4.length = 24cm and breadth = 16cm
Mathematics
2 answers:
hram777 [196]3 years ago
8 0

Answer:

Let's call the width x and the length x + 8. Perimeter can be calculated by multiplying the sum of the length and width by 2 so we can write:

2(x + x + 8) = 80

2(2x + 8) = 80

2x + 8 = 40

2x = 32

x = 16

This means that the length is 16 cm and the width is 24 cm.

sasho [114]3 years ago
6 0

Answer:

the area of rectangle is 384 sq cm, while the length of the rectangle is 24 cm and width of rectangle is 16 cm

Step-by-step explanation:

Let the breadth of the rectangle is x cm  

Thus the length of the rectangle = (x + 8) cm

We know Perimeter = 2 (length + width)

Perimeter = 2 (x + 8 + x)

Perimeter = 2 (2x + 8)

Perimeter = 4x + 16 cm

4x + 16 = 80 cm

4x = 80 - 16

4x = 64

x = 64/4 cm

x = 16 cm

Thus the width of the rectangle is 16 cm

Length of the rectangle x + 8 = 16 + 8 = 24 cm

We know Area of rectangle = length × breadth

Area of rectangle = 24 × 16 = 384 sq cm

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Answer:

The null and alternative hypothesis for this study are:

H_0: \mu=18500\\\\H_a:\mu< 18500

The null hypothesis is rejected (P-value=0.004).

There is enough evidence to support the claim that the average cost of tuition plus room and board at small private liberal arts colleges is  less than $18,500 per term.

Step-by-step explanation:

This is a hypothesis test for the population mean.

The claim is that the average cost of tuition plus room and board at small private liberal arts colleges is  less than $18,500 per term.

Then, the null and alternative hypothesis are:

H_0: \mu=18500\\\\H_a:\mu< 18500

The significance level is 0.05.

The sample has a size n=150.

The sample mean is M=18200.

The standard deviation of the population is known and has a value of σ=1400.

We can calculate the standard error as:

\sigma_M=\dfrac{\sigma}{\sqrt{n}}=\dfrac{1400}{\sqrt{150}}=114.31

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z=\dfrac{M-\mu}{\sigma_M}=\dfrac{18200-18500}{114.31}=\dfrac{-300}{114.31}=-2.624

This test is a left-tailed test, so the P-value for this test is calculated as:

P-value=P(z

As the P-value (0.004) is smaller than the significance level (0.05), the effect is significant.

The null hypothesis is rejected.

There is enough evidence to support the claim that the average cost of tuition plus room and board at small private liberal arts colleges is  less than $18,500 per term.

3 0
3 years ago
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<h3>Answer: Choice A which is (m+6)^2</h3>

Explanation:

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The expression (m+6)(m+6) is the same as (m+6)^2

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