Answer:
10 mystery books
Step-by-step explanation:
Animals:
Multiply the total number of books by the fraction of animal books
4/16*16
4 animal books
Adventure:
2 adventure books
Mystery:
Subtract the number of adventure and animal books from the total number of books
16-4-2
10
10 mystery books
Hope this helps! :)
It’s 3/6 if I’m not mistaken
Yes because it ends or has a repeater (with it doesn’t)
Answer:
2^(8p) =2^(5p+15)
Step-by-step explanation:
16 ^ 2p = 32 ^ (p+3)
Rewrite each number as a power of 2
16 = 2^4
32 = 2^5
2^4 ^ 2p =2^5 ^ (p+3)
We know a^b^c = a^(b*c)
2^(4 * 2p) =2^(5 * (p+3))
2^(8p) =2^(5p+15)
Answer:
![\left[\begin{array}{ccc}2&1&3\\1&2&2\\2&3&1\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D2%261%263%5C%5C1%262%262%5C%5C2%263%261%5Cend%7Barray%7D%5Cright%5D)
![\left[\begin{array}{c}b&y&r\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bc%7Db%26y%26r%5Cend%7Barray%7D%5Cright%5D)
![= \left[\begin{array}{c}1500&1225&1200\end{array}\right]](https://tex.z-dn.net/?f=%3D%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bc%7D1500%261225%261200%5Cend%7Barray%7D%5Cright%5D)
Step-by-step explanation:
Given
Required
Represent as a matrix
For Sammy:
So, we have:
For Jamie:
So, we have:
For Yvonne:
So, we have:
The system of equations are:
To represent as a matrix, we have:
![\left[\begin{array}{ccc}b_1&y_1&r_1\\b_2&y_2&r_2\\b_3&y_3&r_3\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7Db_1%26y_1%26r_1%5C%5Cb_2%26y_2%26r_2%5C%5Cb_3%26y_3%26r_3%5Cend%7Barray%7D%5Cright%5D)
![= \left[\begin{array}{c}Total_1&Total_2&Total_3\end{array}\right]](https://tex.z-dn.net/?f=%3D%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bc%7DTotal_1%26Total_2%26Total_3%5Cend%7Barray%7D%5Cright%5D)
This gives:
