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3 years ago

How could I write the fractions 8/100 3/5 and 7/10 from least to greatest?

Mathematics

2 answers:

baherus [9]3 years ago

8 0

7/10 and then 3/5 and then 8/100

iVinArrow [24]3 years ago

5 0

Get them to have a common denominator. 100 is the common denominator, so change 7/10 and 3/5 to have a denominator of 100. 7/10=70/100 and 3/5=60/100. So from least to greatest it will go 8/100, 3/5, 7/10.

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3 years ago

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2 years ago

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Which number does not belong with the other three?

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One household is to be selected at random from a town. The probability that the household has a cat is 0.20.2 . The proba

dimulka [17.4K]

Answer:

There is a 50% probability that the household has a dog, given that the household has a cat.

Step-by-step explanation:

We solve this problem building the Venn's diagram of these probabilities.

I am going to say that:

A is the probability that a household has a cat.

B is the probability that a household has a dog.

We have that:

$A = a + (A \cap B)$

In which a is the probability that a household has a cat but not a dog and $A \cap B$ is the probability that a household has both a cat and a dog.

By the same logic, we have that:

$B = b + (A \cap B)$

The probability that the household has a cat or a dog is 0.5

$a + b + (A \cap B) = 0.5$

The probability that the household has a dog is 0.4

$B = 0.4$

$B = b + (A \cap B)$

$b = 0.4 - (A \cap B)$

The probability that the household has a cat is 0.2.

$A = 0.2$

$A = a + (A \cap B)$

$a = 0.2 - (A \cap B)$

$a + b + (A \cap B) = 0.5$

$0.2 - (A \cap B) + 0.4 - (A \cap B) + (A \cap B) = 0.5$

$A \cap B = 0.1$

What is the probability that the household has a dog, given that the household has a cat?

20% of the households have a cat, and 10% have both a cat and a dog. So

$P = \frac{A \cap B}{A} = {0.1}{0.2} = 0.5$

There is a 50% probability that the household has a dog, given that the household has a cat.

4 0

2 years ago

Find the measure of angle B, note that angle B is acute

Nesterboy [21]

Answer:

B= 44.9506°

Step-by-step explanation:

WE apply sine angle formula

$\frac{a}{sin(A)} =\frac{b}{sin(B)}=\frac{c}{sin(C)}$

Given angle C = 51, c= 11 and b = 10

$\frac{b}{sin(B)}=\frac{c}{sin(C)}$

Plug in the values

$\frac{10}{sin(B)}=\frac{11}{sin(51)}$

Cross multiply it

10 * sin(51) = 11* sin(B)

7.771459615 = 11 sin(B)

Now divide by 11 on both sides

0.706496328 = sin(B)

Now $B = sin^{-1} (0.706496328)$

B= 44.9506°

3 0

3 years ago