Answer:
sin70°
Step-by-step explanation:
Given sin110° where 110° is an obtuse angle in the second quadrant.
The related acute angle in the first quadrant is 180° - 110° = 70°
Thus
sin110° = sin70°
Using the formula (AB +BC) *BC = (DE +CD) *CD
fill i n what is known:
(17 + 4) *4 = (DE +6) *6
21*4 = (DE +6)*6
84 = (DE+6)*6
84/6 = DE+6
14 = DE +6
DE = 14-6
DE = 8
<h3>Answer:</h3>
A) ∠A = ∠A' = 38° and ∠B = ∠B' = 42°
<h3>Explanation:</h3>
The sum of angles in ∆ABC is 180°, so ...
... (2x -2) + (2x +2) + (5x) = 180
... 9x = 180
... x = 20
and the angles of ∆ABC are ∠A = 38°, ∠B = 42°, ∠C = 100°.
___
The sum of angles of ∆A'B'C' is 180°, so ...
... (58 -x) +(3x -18) +(120 -x) = 180
... x +160 = 180
... x = 20
and ∠A' = 38°, ∠B' = 42°, ∠C' = 100°.
_____
The values of angle measures of ∆ABC match those of ∆A'B'C', so we can conclude ...
... A) ∠A = ∠A' = 38° and ∠B = ∠B' = 42°
The coefficient of these two number are -24 and 7. :)
Some of the important "given" information is outside of the photo.
We need to know that the two triangles are similar.
And we need to know that the WHAT ? of angle M is 9/40.
