Answer:
f'(1)=150ln(1.5)
Step-by-step explanation:
I'm not sure why you would need a table since the limit definition of a derivative (from what I'm remembering) gives you the exact formula anyway... so hopefully this at least helps point you in the right direction.
My work is in the attachment but I do want to address the elephant on the blackboard real quick.
You'll see that I got to the point where I isolated the h's and just stated the limit equaled the natural log of something out of nowhere. This is because, as far as I know, the way to show that is true is through the use of limits going to infinity. And I'm assuming that you haven't even begun to talk about infinite limits yet, so I'm gonna ask you to just trust that that is true. (Also the proof is a little long and could be a question on it's own tbh. There are actually other methods to take this derivative but they involve knowing other derivatives and that kinda spoils a question of this caliber.)
Well, I don't really understand if it is 30 or 305 because of the spacing but I'll answer both. If it is 5y+305, just divide the whole equation by 5 and it will look like this (<u>5y+305)</u> then the factor would be 5(y+61)<u>
</u> 5
If it is 5y+30 it would be just in the same process, Divide the equation by 5 and the result will be 5(y+6).
Answer:
I got 70% hope it helps man
Answer:
1cm = 320 km?
Step-by-step explanation:
Answer:
30
Step-by-step explanation:
150+30=180
Hope This Helps!!
(brainliest please, if possible)