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Alexeev081 [22]
3 years ago
13

Find the sum of the first 69 terms of the arithmetic sequence.

Mathematics
1 answer:
BartSMP [9]3 years ago
7 0

Answer:

66.4637681159

Step-by-step explanation:

add the 69 numbers and divide by 69 for how many terms there are

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ivolga24 [154]

2: 4 is a factor and multiple of 8. 8 and 4 is also even numbers so is is most likely to be divisible by any number

4 0
4 years ago
Hurry up someone please
Lostsunrise [7]

Answer:

x = 19.6

Step-by-step explanation:

If we need to find the value of x then first we need to

(7x-25) + (3x +9) = 180  (angles at the same side of transversal will be equal to 180 degree )

10x -16 = 180

10x = 180 +16

10x = 196

x = 196/10

x = 19.6

4 0
3 years ago
One container is filled with mixture that is 25% acid. A second container is filled with a mixture that is 55% acid. The second
algol13

Answer:

Therefore the third container contains   \frac{735}{17}\% = 43.23 %  acid.

Step-by-step explanation:

Given that, One container is filled with the mixture that 25% acid. 55% acid is contain by second container.

Let the volume of first container be x cubic unit.

Since the volume of second container is 55% larger than the first.

Then the volume of the second container is

= (V\times \frac{100+55}{100})   cubic unit.

=\frac{155}{100}V  cubic unit.

The amount of acid in first container is

=V\times \frac{25}{100}  cubic unit.

=\frac{25}{100}V  cubic unit.

The amount of acid in second container is

=(\frac{155}{100}V \times \frac{55}{100}) cubic unit.

=\frac{8525}{10000}V cubic unit.

Total amount of acid =(\frac{25}{100}V+\frac{8525}{10000}V) cubic unit.

                                   =(\frac{2500+8525}{10000}V) cubic unit.

                                   =(\frac{11025}{10000}V)cubic unit.

Total volume of mixture =(V+\frac{155}{100}V) cubic unit.

                                       =\frac{100+155}{100}V cubic unit.

                                       =\frac{255}{100}V  cubic unit.

The amount of acid in the mixture is

=\frac{\textrm{The volume of acid}}{\textrm{The amount of mixture}}\times 100 \%

=\frac {\frac{11025}{10000}V}{\frac{255}{100}V}\times 100\%

=\frac{735}{17}\%

Therefore the third container contains  \frac{735}{17}\%  acid.

5 0
3 years ago
Evaluate f(g(5)) if F (x) = 5x + 2 and g (x) =X2 -4
Monica [59]

Answer:

Step-by-step explanation:

g(5) = 5^2 - 4 = 25 - 4 = 21

f(21) = 5(21) + 2 = 105 + 2 = 107

7 0
3 years ago
Help please. this is really hard for me to understand.
bogdanovich [222]

Answer:

1. x = - 4, - 3

2. x = 9, - 1

3. x = - 1, 10

4. x = - 8, - 3

8 0
3 years ago
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