Answer:
nnnnnnnnnnnnnnmnnnnnnnnnnnnnnnnnnnnnnnnnn
Step-by-step explanation:
Answer is c
a and d are crossed off because the action of going up and down is adding and subtracting. Absolute values of any number is a positive. So b and c are left. Then b is crossed out because the is subtracting each value from another which affects the result. Negatives change signs. Positives don't. So you want an equation that sums up all individual values without affect the signs. Answer is C.
I can’t really do long division on a phone so, extended techniques are required.
(x^3 - 2x^2 + 6x + 3)/(x-3)
= (x^3 - 3x^2 + (x^2 - 6x + 9)+ 12x - 6)/(x-3)
= (x^2(x-3) + (x-3)^2 + 6(2x - 1))/x-3
= x^2 + x - 3 + 6(2x - 1)/(x-3)
or
= x^2 + x - 3 remainder 12x - 6
or, in the form p(x) = q(x)d(x) + r(x):
(x^3 - 2x^2 + 6x + 3) = (x^2 + x - 3)(x - 3) + (12x - 6)
which implies that the quotient q(x) = (x^2 + x - 3) and remainder r(x) = 12x - 6