Let the least possible value of the smallest of 99 cosecutive integers be x and let the number whose cube is the sum be p, then

By substitution, we have that

and

.
Therefore, <span>the least possible value of the smallest of 99 consecutive positive integers whose sum is a perfect cube is 314.</span>
Answer:
3x-1
Step-by-step explanation:
6 +(-x) +2x + (-7) + 2x=
6-x +2x -7 + 2x =
6-7+ 2x+2x-x=
-1 + 3x=
3x-1
Answer:
Step-by-step explanation:


= 0.44 <- rounded to the nearest hundredth
X plus the 28 degree equals 90
so x = 90-28 = 62 degrees
are you trying to add them all together if so here how that would work
4x-3x=1x
2y-(1)y =1y(if the y is alone theirs a 1 always infront of it)
-14-8=-22