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yan [13]
4 years ago
13

A perpendicular bisector intersects line segment A C at point B. The bisector also contains points E and D. Line segment A B is

3 x minus 2. Line sector A D is 8 x minus 1. Line sector D C is 6 x + 9.
What is the measure of AC?
5 units
13 units
26 units
39 units

Mathematics
2 answers:
sdas [7]4 years ago
7 0

Answer:

(C)26 units

Step-by-step explanation:

Since point B bisects AC into two equal parts

AB=BC

Since the two right triangles have side BD in common, we can then say that the two triangles are congruent and the length of the hypotenuses (AD and DC) are equal.

If AD=DC

8x-1=6x+9

8x-6x=9+1

2x=10

x=5

Now,

AB=3x-2

=3(5)-2

=13 Units

Since AB=BC

AC=AB+BC

=13+13

AC=26 units

The measure of AC is 26 units.

Anettt [7]4 years ago
3 0

Answer:

26 units

Step-by-step explanation:

100% the answer just did it

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Helga [31]

Answer:

#1 is 2

#2 is -2/3

#3 is -2/5

#4 is -1/2

#5 is 4

#6 is 1

Step-by-step explanation:

I hope this helps

4 0
3 years ago
a photo album contains small and large photographs. Each large photograph has side lengths that are twice the side lengths of ea
zysi [14]
Take the area of the small photograph and divide it by four, assuming it's a square, each side would then be 6 inches. The large photograph has double the side length of the small one, so 6 multiplied by 2 is 12. To find the area of the large (square) photograph, multiply 12 by 12 as two of the sides, and the area of the large photo is 144 square inches
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Why are the solutions to the proportions 50/x =10/20 and 10/50=20/x the same
ratelena [41]
With cross multiplication you can find that they are the same. In both equations, x would be 100. 
5 0
3 years ago
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A rectangular prism has a length of 11 mm and with a 5 mm. Its height is double its weight. What is the surface area of the pris
kkurt [141]

Answer:

C. 430

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length: 11

weight: 5

height (double of weight): 10

2 * (5 * 11 + 10 * 11 + 10 * 5)= 430

4 0
3 years ago
In a competition, a school awarded medals in different categiories.40 medals in sport 25 medals in danceand 212 medals in music,
aleksley [76]

Answer:

210

Step-by-step explanation:

Given:

Medals in sports = 40

Medals in dance = 25

Medals in music = 212

Total students that received medals = 55

Total students that received medals in all three categories = 6

Required:

How many students get medals in exactly two of these categories?

Take the following:

A = set of persons who got medals in sports.

B = set of persons who got medals in dance

C = set of persons who got medals in music.

Therefore,

n(A) = 40

n(B) = 25

n(C) = 212

n(A∪B∪C)= 55

n(A∩B∩C)= 6

To find how many students get medals in exactly two of these categories, we have:

n(A∩B) + n(B∩C) + n(A∩C) −3*n(A∩B∩C)

=n(A∩B) + n(B∩C) + n(A∩C) −3*6 ……............... (1)

n(A∪B∪C)=n(A)+n(B)+n(C)−n(A∩B)−n(B∩C)−n(A∩C)+n(A∩B∩C)

Thus, n(A∩B)+n(B∩C)+n(A∩C)=n(A)+n(B)+n(C)+n(A∩B∩C)−n(A∪B∪C)

Using equation 1:

=n(A)+n(B)+n(C)+n(A∩B∩C)−n(A∪B∪C)−18

Substitute values in the equation:

= 40 + 25 + 212 + 6 − 55 − 18

= 283 - 73

= 210

Number of students that get medals in exactly two of these categories are 210

6 0
4 years ago
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