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3 years ago

Write this trinomial in factored form. 3b^2+b-14

Mathematics

1 answer:

Makovka662 [10]3 years ago

4 0

Answer:

(b - 2)(3b + 7)

Step-by-step explanation:

Consider the factors of the product of the coefficient of the b² term and the constant term which sum to give the coefficient of the b- term

product = 3 × - 14 = - 42 and sum = + 1

The factors are - 6 and + 7

Use these factors to split the b- term

3b² - 6b + 7b - 14 ( factor the first/second and third/fourth terms )

= 3b(b - 2) + 7(b - 2) ← factor out (b - 2) from each term

= (b - 2)(3b + 7) ← in factored form

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Write this trinomial in factored form. 3b^2+b-14​

Write this trinomial in factored form. 3b^2+b-14