Answer:
(b - 2)(3b + 7)
Step-by-step explanation:
Consider the factors of the product of the coefficient of the b² term and the constant term which sum to give the coefficient of the b- term
product = 3 × - 14 = - 42 and sum = + 1
The factors are - 6 and + 7
Use these factors to split the b- term
3b² - 6b + 7b - 14 ( factor the first/second and third/fourth terms )
= 3b(b - 2) + 7(b - 2) ← factor out (b - 2) from each term
= (b - 2)(3b + 7) ← in factored form
