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nekit [7.7K]
3 years ago
7

A metalworker has a metal alloy that is 30% copper and another alloy that is 65% copper. How many kilograms of each alloy should

the metalworker combine to create 80kg of a 51% copper alloy?
Mathematics
1 answer:
LenKa [72]3 years ago
7 0

Step-by-step explanation:

If x is the mass of 30% copper alloy, and y is the mass of 65% copper alloy, then:

x + y = 80

0.30x + 0.65y = 0.51(80)

Solving the system of equations using substitution:

0.30x + 0.65(80 − x) = 0.51(80)

0.30x + 52 − 0.65x = 40.8

11.2 = 0.35x

x = 32

y = 80 − x

y = 48

The metalworker needs 32 kg of 30% copper alloy and 48 kg of 65% copper alloy.

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Answer:

$40

Step-by-step explanation:

Turn the percentage into a decimal.

80% = 0.8

Multiply.

50 * 0.8 = 40

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Answer:

  29.15 in

Step-by-step explanation:

The area of a rectangle is given by the formula ...

  A = LW

Filling in the given information, we can find the missing side length.

  297 in² = (27 in)h

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The length of the diagonal can be found from the Pythagorean theorem.

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7 0
3 years ago
Simplest form equivalent to 3y + y + 2y - 4y
bixtya [17]

Answer:

4y+6y

Step-by-step explanation

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7 0
3 years ago
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Lapsed time 2:45-5:15
Arturiano [62]
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5 0
3 years ago
Please help
nikitadnepr [17]

Answer:

The value of x is \frac{-2}{5}.

Step-by-step explanation:

Given expression is:

\frac{2}{3}(x-2)=4x

We have to solve this for x.

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3*\frac{2}{3}(x-2)=4x*3

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Now we will be subtracting 2x from both sides of the equation

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8 0
3 years ago
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