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Gennadij [26K]
3 years ago
11

Write a expression that shows how to multiply 4 x 362 using place value and expanded form??

Mathematics
1 answer:
dexar [7]3 years ago
3 0

Answer:


Step-by-step explanation:


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Please help, I will give Brainliest to whoever answers! <3
Rufina [12.5K]

Answer:

the answer is c i did the test

Step-by-step explanation:

pls i did the test trust me.

7 0
3 years ago
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Which statements must be true regarding the diagram?<br> (please check more than one answer)
nikdorinn [45]
Try this option:
- true;
- not true;
- true;
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4 0
3 years ago
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Find the area of a circle with a Radius = 4 ft. Use 3.14 for and round to 2 decimal places.
bagirrra123 [75]

Answer:

50.24 ft^2

Step-by-step explanation:

Well formula for area of a circle is pi(radius)^2

so the radius is 4 so you square that it’ll be 16

then do 16(3.14)

you’ll get 50.24

6 0
3 years ago
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Determine the shortest segment in △ PQS and △ QRS. Remember that a segment is named by its endpoints (two letters).
irinina [24]

Answer: QS and QR are the shortest segment of the triangle ΔPQS, and ΔSQR respectively.

Step-by-step explanation:

Since we have given that

ΔPQS, and ΔSQR,

Consider, ΔPQS,

As we know that " the length opposite to the largest angle is the shortest segment."

So, According to the above statement.

\angle QPS=63\textdegree\\\\\text{So, QS is the shortest segment of this triangle}

Similarly,

Consider, ΔSQR,

Again applying the above statement, we get that,

\angle QSR=75\textdegree\\\\\text{ So, QR is the shortest segment of this triangle}

Hence, QS and QR are the shortest segment of the triangle ΔPQS, and ΔSQR respectively.



8 0
3 years ago
a plane flying with the wind travels 630 mi in 1.5hrs. Flying against the wind , the plane travels 1120 mi in 4hrs. Find the rat
Flauer [41]
\bf \begin{cases}&#10;r=\textit{rate of the plane}\\&#10;w=\textit{rate of the wind}\\&#10;\end{cases}&#10;\\\\&#10;&#10;\begin{array}{ccccllll}&#10;&distance&rate&time(hrs)\\&#10;&\textendash\textendash\textendash\textendash\textendash\textendash&\textendash\textendash\textendash\textendash\textendash\textendash&\textendash\textendash\textendash\textendash\textendash\textendash\textendash\textendash\textendash\\&#10;\textit{with wind}&630&r+w&1\frac{1}{2}\\&#10;\textit{against wind}&1120&r-w&4&#10;\end{array}&#10;

\bf thus  \begin{cases}&#10;630=(r+w)1\frac{1}{2}\to 630=(r+w)\frac{3}{2}&#10;\\\\&#10;1120=(r-w)4\\&#10;--------------\\&#10;630=(r+w)\frac{3}{2}\implies 630\cdot \frac{2}{3}=r+w\\&#10;420=r+w\implies \boxed{420-w}=r\\&#10;--------------\\&#10;thus\\&#10;--------------\\&#10;1120=(r-w)4\implies 1120=4r-4w&#10;\\\\&#10;1120=4(\boxed{420-w})-4w&#10;\end{cases}&#10;

solve for "w", to find the wind's speed rate,

so hmmm what's the plane's rate?  well 420 - w = r  :)
5 0
3 years ago
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