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3 years ago

Since you guys said you couldn't see it last I reuploaded

Mathematics

2 answers:

prisoha [69]3 years ago

7 0

It’s blank is the answer lol we can’t see it

Aleonysh [2.5K]3 years ago

3 0

Yeah bro it’s till blank

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The dolphins scored 2x - 7 points, while the jaguars scored -5x - 3 points. how many more points did the dolphins score than the

mr Goodwill [35]

2x-7 -(-5x-3) =
2x-7+5x+3=
7x-4 is the answer

6 0

3 years ago

A footbridge is 5 feet wide and is built with wood planks that are 6 inches wide. How many planks wide is the path?

Ede4ka [16]

Here we have to know the conversion between feet and inches.

1 Feet = 12 inches (This is given and is to be known)

So the 5 feet wide footbridge when converted to inches would be about 5*12 = 60 inches

The width of the footbridge in inches = 60 inches

Each wooden plank is 6 inches,

So the number of wooden planks that are required to build the foot bridge of 60 inches = 60/6 = 10 planks

Hence, the path path is 10 planks wide

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3 years ago

A British company is sending you measurements for a table to build in your factory. The table top must be 50 cm x 75 cm. Your ma

Degger [83]

Answer:

<h2>Answer is B!</h2>

Step-by-step explanation:

<h2>Mutiply 0.39*50=19.5</h2><h2>Mutiply 0.39*75=29.25</h2>

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3 years ago

Joanne budgets $880 each month for fixed expenses. What percent of her net monthly income is that if she nets $1960 semimonthly

Alex Ar [27]

B: 36% i hope i helped u out

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3 years ago

Read 2 more answers

HELP! Find the value of sin 0 if tan 0 = 4; 180 < 0< 270

BabaBlast [244]

Hi there! Use the following identities below to help with your problem.

$\large \boxed{sin \theta = tan \theta cos \theta} \\ \large \boxed{tan^{2} \theta + 1 = {sec}^{2} \theta}$

What we know is our tangent value. We are going to use the tan²θ+1 = sec²θ to find the value of cosθ. Substitute tanθ = 4 in the second identity.

$\large{ {4}^{2} + 1 = {sec}^{2} \theta } \\ \large{16 + 1 = {sec}^{2} \theta } \\ \large{ {sec}^{2} \theta = 17}$

As we know, sec²θ = 1/cos²θ.

$\large \boxed{sec \theta = \frac{1}{cos \theta} } \\ \large \boxed{ {sec}^{2} \theta = \frac{1}{ {cos}^{2} \theta} }$

And thus,

$\large{ {cos}^{2} \theta = \frac{1}{17}} \\ \large{cos \theta = \frac{ \sqrt{1} }{ \sqrt{17} } } \\ \large{cos \theta = \frac{1}{ \sqrt{17} } \longrightarrow \frac{ \sqrt{17} }{17} }$

Since the given domain is 180° < θ < 360°. Thus, the cosθ < 0.

$\large{cos \theta = \cancel\frac{ \sqrt{17} }{17} \longrightarrow cos \theta = - \frac{ \sqrt{17} }{17}}$

Then use the Identity of sinθ = tanθcosθ to find the sinθ.

$\large{sin \theta = 4 \times ( - \frac{ \sqrt{17} }{17}) } \\ \large{sin \theta = - \frac{4 \sqrt{17} }{17} }$

Answer

sinθ = -4sqrt(17)/17 or A choice.

4 0

3 years ago