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3 years ago

PLZ help dividing exponents 7^12 ÷ 7^4 is equal to _____. 1^3 3 7^3 7^8

Mathematics

2 answers:

son4ous [18]3 years ago

5 0

Answer:

7^8

Step-by-step explanation:

Find what each exponent equals

7^12 equals 13,841,287,201

7^4 equals 2,401

Divide the two numbers

It equals 5,764,801 which is equivalent to 7^8

Nostrana [21]3 years ago

3 0

Answer:

7^8

Step-by-step explanation:

did this so you could give the other person brainlyist

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The sum of a number and 15

ollegr [7]

Answer:

x + 15

Step-by-step explanation:

The problem is in word form. Write the problem in algebraic form, which means using numbers and symbols (like + - ÷ x).

Take the key word:

'sum' - This means the answer when you add numbers. To add you use the + plus sign.

The sum of a number and 15 means adding a number and 15.

There is no equal sign because the question does not say "equals" or "is".

Choose a variable to represent "a number". I will choose the letter 'x'. Add 15 to 'x'.

x + 15

6 0

3 years ago

pls help will give brainliest Rena used the steps below to evaluate the expression (StartFraction (x Superscript negative 3 Base

kaheart [24]

Answer:

First "order of operations" mistake: step 2

First arithmetic mistake: step 4

Step-by-step explanation:

As we understand Rena's work, she wants to simplify ...

$\left(\dfrac{x^{-3}y^{-2}}{2x^4y^{-4}}\right)^{-3}$

for x = -1 and y = 2.

Her work seems to be ...

Step 1

$\text{Substitute $x=-1$ and $y=2$ into the expression}\\\\\left(\dfrac{(-1)^{-3}2^{-2}}{2(-1)^42^{-4}}\right)^{-3}\qquad\text{no error}$

Step 2

$\text{Simplify the parentheses}\\\\\left(\dfrac{2^4}{2(-1)^4(-1)^32^2}\right)^{-3}=\left(\dfrac{2^2}{2(-1)^7}\right)^{-3}\qquad\text{order of operations error}$

Step 3

$\text{Evaluate the power to a power}\\\\\dfrac{2^{-6}}{2^{-3}(-1)^{21}}\qquad\text{no error}$

Step 4

$\text{Use reciprocals and find the value}\\\\\dfrac{1}{2^32^6(-1)^{21}}=\dfrac{1}{8\cdot 64\cdot (-1)}=\dfrac{-1}{512}\qquad\text{error: $2^3$ is used instead of $2^{-3}$}$

_____

So, the first arithmetic error is in Step 4. However, the order of operations requires exponents be evaluated first. Doing that makes step 2 look like ...

$\left(\dfrac{-\dfrac{1}{4}}{2(1)\dfrac{1}{16}}\right)^{-3}=(-2)^{-3}\qquad\text{proper Step 2}$