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3 years ago

4.) The number -5/8 belongs to the set of (irrational or rational) numbers.

Mathematics

1 answer:

alexandr1967 [171]3 years ago

5 0

Answer:

irrational

Step-by-step explanation:

-5/8 is irrational

hope it helps you

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1/2 ÷ 3 = ? /2 × 1/2

7nadin3 [17]

Answer:

12÷3=4

.2*1.2=0.24..

8 0

3 years ago

I am have trouble with these x-intercepts. Please help me.

kotegsom [21]

Answer:

x=8, x=2
no solution
no solution

Step-by-step explanation:

For the equation ...

y = a(x -h)² +k

you can find the x-intercepts by setting y=0 and solving for x.

0 = a(x -h)² +k

-k = a(x -h)² . . . . . . subtract k

-k/a = (x -h)² . . . . . divide by a

±√(-k/a) = x -h . . . . take the square root

h ± √(-k/a) = x . . . . add h . . . . this is the general solution

So, for each of your problems, fill in the corresponding numbers and do the arithmetic. If (-k/a) is a negative number, the square root gives imaginary values, so there is "no solution".

1. x = 5 ± √9 = {5 -3, 5 +3} = {2, 8} . . . . the x-intercepts are 2 and 8

2. x = -3 ± √(-2) . . . . . . no solution; the roots are complex

3. x = 5 ± √(-8/4) . . . . . no solution; the roots are complex

7 0

3 years ago

Read 2 more answers

What answers can their be in the numbers 3,7,12,2 in order of operations

Sever21 [200]

3 × 7 × 12 × 2
3 + 7 + 12 + 2
12 - 7 - 3 - 2

5 0

3 years ago

HI decomposes into its elements according to second-order kinetics. What concentration of HI remains from an initial concentrati

Novosadov [1.4K]

Answer:

Therefore (2.30-0.03747)= 2.2625 M of HI remains from an initial concentration of 2.30 M after 4.5 hours.

Step-by-step explanation:

second order reaction: The rate of reaction proportional to the square of the concentration of reactant.

For second order reaction

$k=\frac{x}{ta(a-x)}$

K is rate constant = 1.6×10⁻³M⁻¹hr⁻¹

a = initial concentration of reactant = 2.30 M

a-x = concentration of reactant after t h

t = time = 4.5 h

Putting the values in the above equation,

$1.6\times 10^{-3}= \frac{x}{4.5 \times 2.30 \times (2.30-x)}$

$\Rightarrow 16.56 \times 10^{-3}\times (2.30-x)= x$

$\Rightarrow 16.56 \times 10^{-3}\times 2.30-16.56 \times 10^{-3}\times x= x$

$\Rightarrow (1+16.56 \times 10^{-3}) x=16.56 \times 10^{-3}\times 2.30$

$\Rightarrow x = 0.03747$

Therefore (2.30-0.03747)= 2.2625 M of HI remains from an initial concentration of 2.30 M after 4.5 hours.

4 0

4 years ago

Is AB parallel to CD?

Katen [24]

You have to evaluate the slopes of these lines. For line AB you have a slope of
$\frac{1 - ( - 3)}{0 - ( - 3)} = \frac{4}{3}$
For line CD you have a slope of
$\frac{ - 1 - ( - 5)}{3 - 0} = \frac{4}{3}$
Because the slopes are equal and the two lines are not one and the same, they are parallel.

6 0

3 years ago