Answer: 1559
Step-by-step explanation: Just add 10 hours and 12 minutes to 0547. 10 hours after 0547 in military time would be 1559.
Answer:
y=-3×5
so'n
y=-15ans
another has no number only one number 2 alphabets
The question is incomplete. Here is the complete question:
Samir is an expert marksman. When he takes aim at a particular target on the shooting range, there is a 0.95 probability that he will hit it. One day, Samir decides to attempt to hit 10 such targets in a row.
Assuming that Samir is equally likely to hit each of the 10 targets, what is the probability that he will miss at least one of them?
Answer:
40.13%
Step-by-step explanation:
Let 'A' be the event of not missing a target in 10 attempts.
Therefore, the complement of event 'A' is 
Now, Samir is equally likely to hit each of the 10 targets. Therefore, probability of hitting each target each time is same and equal to 0.95.
Now, 
We know that the sum of probability of an event and its complement is 1.
So, 
Therefore, the probability of missing a target at least once in 10 attempts is 40.13%.
Answer:
x+75=180
x=180-75
x=105
Step-by-step explanation:
x and a are on a straight line
a straight line=180
so you add the x to a=180
The distance from A to B will be negative when the line is trending downward from left to right.