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Ymorist [56]
3 years ago
7

NEED HELP ASAP SHOW WORK AND PLZ EXPLAIN

Mathematics
1 answer:
Rainbow [258]3 years ago
3 0

Answer:

x = 12

Step-by-step explanation:

Given

4(x - 5) = 8x + 4 - 6x ← distribute left side and simplify right side

4x - 20 = 2x + 4 ( subtract 2x from both sides )

2x - 20 = 4 ( add 20 to both sides )

2x = 24 ( divide both sides by 2 )

x = 12

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In the expression 2a + 5 + a -14 + 3b which ones are the constants​
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5

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Constant= # without variable

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How can I show my work on these answers 31x 7. 29x4
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A walker and a cyclist are 45 miles apart. They move towards each other with speeds of 5 mph and 10 mph respectively. In how man
Ymorist [56]

Answer: they will meet after 3 hours.

Step-by-step explanation:

Let t represent the number of hours it will take them to meet.

A walker and a cyclist are 45 miles apart. If they move towards each other, in t hours, they would have covered a total of 45 miles

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They move towards each other with speeds of 5 mph and 10 mph respectively. It means that the distance covered by the walker in t hours is 5 × t = 5t

Also, the distance covered by the cyclist in t hours is 10 × t = 10t

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4 0
3 years ago
Use the given zero to find the remaining zeros of each function f(x)=2x^4+5x^3+5x^2+20x-12 zero:-2i
frutty [35]

Answer:

1/2, 3

Step-by-step explanation:

This is a pretty involved problem, so I'm going to start by laying out two facts that our going to help us get there.

  1. The Fundamental Theorem of Algebra tells us that any polynomial has <em>as many zeroes as its degree</em>. Our function f(x) has a degree of 4, so we'll have 4 zeroes. Also,
  2. Complex zeroes come in pairs. Specifically, they come in <em>conjugate pairs</em>. If -2i is a zero, 2i must be a zero, too. The "why" is beyond the scope of this response, but this result is called the "complex conjugate root theorem".

In 2., I mentioned that both -2i and 2i must be zeroes of f(x). This means that both x-2i and x+2i are factors of f(x), and furthermore, their product, x^2+4, is <em>also</em> a factor. To see what's left after we factor out that product, we can use polynomial long division to find that

2x^4+5x^3+5x^2+20x-12=(x^2+4)(2x^2+5x-3)

I'll go through to steps to factor that second expression below:

2x^2+5x-3=2x^2+6x-x-3\\=2x(x+3)-(x+3)\\=(2x-1)(x+3)

Solving both of the expressions when f(x) = 0 gets us our final two zeroes:

2x-1=0\\2x=1\\x=1/2

x+3=0\\x=-3

So, the remaining zeroes are 1/2 and 3.

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3 years ago
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