Yes it is possible. Consider the following scenarios
Scenario A:
Min = 5
Q1 = 10
Median = 12
Q3 = 18
Max = 22
The IQR is equal to the difference of Q3 and Q1
IQR = Q3-Q1 = 18-10 = 8
The range is the difference of the min and max
Range = Max - Min = 22 - 5 = 17
So in summary for scenario A, we have
IQR = 8
Range = 17
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Now consider another scenario, call it scenario B, where
Min = 100
Q1 = 102
Median = 105
Q3 = 110
Max = 117
I claim that the IQR and Range for scenario B is going to be the same as in Scenario A. Let's find out
IQR = Q3 - Q1 = 110 - 102 = 8
Range = Max - Min = 117 - 100 = 17
So
IQR = 8
Range = 17
which is identical to scenario A.
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Scenario B has completely different data than scenario A, yet the IQR and Range are equal to scenario A's counterparts. This shows that it is possible to have 2 completely sets of data yet have the same IQR and range.
The wrap up here, and the answer to the question, is "yes it is possible" with the explanation given above.
take a factor of 6 out to make 6(4x-3)
Dunno what the work backward way is
seeems hard
maybe it's trial and error?
anyway
algebreaic
2n+5<13
minus 5 both sides
2n<8
divide by 2
n<4
Answer:
x=-7
Step-by-step explanation:
Alrighty. 5x+8=2x-13. Lets do -2x on both sides. We'll get 3x+8=-13. Then lets subtract 8 from both sides. We'll get 3x=-21. Divide by 3 and we'll get x=-7. Hope that makes sense.
In any equation with variables, you want to end with a variable isolated on one side with no coefficients(like x=4, for instance).
So, with that in mind, let's solve number 2.
5(x-3) - 2(2x+4) = -2(x-2)
Let's distribute the coefficients.
(5x-15)-(4x+8) = (-2x+4)
Simplify the left side first (by subtracting the two)
5x-4x = x
-15 - (+)8 = -23
So, left side is
x-23 = -2x+4
We're close now, just bring the x to the left side and the other values to the right
x-23 = -2x+4
+23 +23
x=-2x+27
+2x +2x
3x=27
divide by 3
x=9
3.
3(4x-5)-2(2x-2)=4(3x-2)+5
Same idea here; distribute the coefficients, and simplify.
(12x-15)-(4x-4)=(12x-8)+5
12x-4x=8x
-15-(-)4=-11
-8+5=-3
8x-11=12x-3
bring x to left, other numbers to right
-12x -12x
+11 +11
-4x = 8
divide by -4
x=-2
