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3 years ago

Could these side lengths make a right triangle, 12m, 35m and 37m

Mathematics

1 answer:

natta225 [31]3 years ago

3 0

Answer:

Yes

Step-by-step explanation:

Using Pythagorean theorem WHICH ONLY WORKS FOR RIGHT TRIANGLES,

a^2+b^2=c^2 where a and b are the two shortest legs.

12^2+35^2=c^2

144+1225=c^2

c^2=1369

c= $\sqrt{1369}$

c=37

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All the fourth-graders in a certain elementary school took a standardized test. A total of 85% of the students were found to be

Aneli [31]

Answer:

There is a 2% probability that the student is proficient in neither reading nor mathematics.

Step-by-step explanation:

We solve this problem building the Venn's diagram of these probabilities.

I am going to say that:

A is the probability that a student is proficient in reading

B is the probability that a student is proficient in mathematics.

C is the probability that a student is proficient in neither reading nor mathematics.

We have that:

$A = a + (A \cap B)$

In which a is the probability that a student is proficient in reading but not mathematics and $A \cap B$ is the probability that a student is proficient in both reading and mathematics.

By the same logic, we have that:

$B = b + (A \cap B)$

Either a student in proficient in at least one of reading or mathematics, or a student is proficient in neither of those. The sum of the probabilities of these events is decimal 1. So

$(A \cup B) + C = 1$

In which

$(A \cup B) = a + b + (A \cap B)$

65% were found to be proficient in both reading and mathematics.

This means that $A \cap B = 0.65$

78% were found to be proficient in mathematics

This means that $B = 0.78$

$B = b + (A \cap B)$

$0.78 = b + 0.65$

$b = 0.13$

85% of the students were found to be proficient in reading

This means that $A = 0.85$

$A = a + (A \cap B)$

$0.85 = a + 0.65$

$a = 0.20$

Proficient in at least one:

$(A \cup B) = a + b + (A \cap B) = 0.20 + 0.13 + 0.65 = 0.98$

What is the probability that the student is proficient in neither reading nor mathematics?

$(A \cup B) + C = 1$

$C = 1 - (A \cup B) = 1 - 0.98 = 0.02$

There is a 2% probability that the student is proficient in neither reading nor mathematics.

6 0

3 years ago

4) A rectangular court is 4 feet wide. The length is twice as long as the width. What is the area of the rectangular court?

Advocard [28]

for rectangles:

A = lw

A = 4(4 * 2)

A = 4(8)

A = 32

So, your answer is B) 32 ft.

8 0

3 years ago

Can someone please send help :(

nlexa [21]

(f o g)(x)

g(x) = x + 2

Since it’s telling you to use g(x), you use (x + 2) as your new x value for function f.

f(x + 2) = 5(x + 2) + 5
= 5x + 10 + 5
= 5x + 15

5 0

3 years ago

Jill is factoring the expression 13XY -52y. Her work is shown below

Sunny_sXe [5.5K]

Answer:13y(x-4)

Step-by-step explanation:

13xy-52y =13y(x-4)

3 0

3 years ago

PLZ HELP MARKIN BRAINIEST!!!

Dahasolnce [82]

From the graph, when x = 1, y = 57,000.

Replace x with 1 in the equations and see if any of the Y 's equal 57,000 :

y = -2610.82(1) + 47860.82 = 45,250

y = 219(1)^2 - 6,506.78(1) + 59,385 = 219 - 6506.78 + 59385 = 53,097.22

y = 54041.5(0.9)^1 = 48,637.35

y = 10,504.6 (1.1)^1 = 11,555.06

The second equation is the closest. so try another x value to see if it is close to the Y value:

Let's try x = 14:

y = 219(14)^2 - 6506.78(14) + 59,385 = 42924 - 91094.92 + 59385 = 11,214.08

This is close to Y = 12,00 shown on the graph

SO the closest equitation is y = 219x^2 - 6506.78x + 59385

8 0

3 years ago