Answer:
2587mm^3 approx!
Step-by-step explanation:
first you divide the nut into 6 part(in triangle now, by joining centre to each edge)
let's take one part of the triangular shape then area of that part can be found by using 1/2×base×height
i.e, 1/2×13×15=97.5(mm^2)
now when we consider depth of that traingular part,we will get volume of that part as area×depth
i.e, 97.5×6=585(mm^3)
now volume of all the 6 triangular part is 585×6=3510(in mm^3)
now take circular cavity in consideration, it's volume will be π(7^2)6=923(mm^3) approximately
now reqired volume will be volume of that hexagonal part minus that of circular cavity
=3510-923
=2587mm^3
✌️
Answer:
x≤ −2/3y + −1/3
Step-by-step explanation:
because...
Step 1: Add -4y to both sides.
6x + 4y + −4y ≤ −2+−4y
6x ≤ −4y −2
Step 2: Divide both sides by 6.
6x/6 ≤ 
x ≤ −2/3y + −1/3
Therefor, the answer is x≤ −2/3y + −1/3
* Hopefully this helps:) Mark me the brainliest:)!!
Answer
no he gave him a dollar extra. if his total is 38.70 and gave 50 if you subtract it would be 11.30 not 12.30
Step-by-step explanation:
It took me awhile, but using the Rational Root Theorem and then synthetic division I got the first root. If you don't know the RRT you'll be in heaps of trouble doing this type of problem. I found the first root to be (x+6), then I did it again and got another root of (x+6) and the third one was (x-5). So the roots of this polynomial (and there are 3 because this is a 3rd degree polynomial) are (x+6) with a multiplicity of 2, and (x-5).
Answer:
the answer is 1.
Step-by-step explanation:
=−1−(−2)
=−1+2
=1
