Calculate the average rate of change for the function f(x) = −x4 + 4x3 − 2x2 + x + 1, from x = 0 to x = 1.

1 answer:

6 0

<span>For the answer to the question above,
The average rate of change = [f(1)-f(0)] /(1-0)

f(x) = -x^4+4x^3-2x^2+x+1
Then substitute it with the given value,
f(1) = -1+4-2+1+1 = 3
Then simplify and solve.

f(0) = 1
[f(1)-f(0)] /(1-0) = (3-1)/1 = 2</span><span>I hope my answer helped you</span>

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A taxi driver had 50 fares to and from the airport last Monday. The price for a ride to the airport is $10, and the price for a

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Answer:

Number of Fares to airport is 25 and number of fares from airport is 25.

Step-by-step explanation:

Given:

Total Number of fares =50

Let number of fares to airport be x.

Let number of fares from airport be y.

hence the equation can be framed as;

$x+y=50 \ \ \ \ equation \ 1$

Also Given

Total Money Collected = $375

Cost to airport = $10

Cost from Airport = $5

Total Money Collect is equal to Cost to airport multiplied by number of Fares to airport plus Cost from airport multiplied by number of Fare from airport.

$10x+5y=375$

Dividing by 5 on both side we get;

$2x+y = 75 \ \ \ \ equation \ 2$

Now Subtracting equation 1 from 2 we get;

$(2x+y)-(x+y)=75-50\\2x+y-x-y=25\\x=25$

Substituting the value of x in equation 1 we get;

$x+y=50\\25+y=50\\y=50-25\\y=25$

Hence Number of Fares to airport is 25 and number of fares from airport is 25.

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<h3>How to calculate the total annual premium for $x ?</h3>

If its given that the annual premium is $p per $y face value, then we can calculate the annual premium for $1 face value and then use it to calculate annual premium for $x.

Using proportions, we get:

$\rm \$y \: face \: value : \$p \: annual \: premiun\\\\\rm \$1 \: face \: value : \$\dfrac{p}{y} \: annual \: premiun\\\\\rm \$x\:face\: value : \$\dfrac{p \times x}{y} \: annual \: premiun\\$

For given case, from the tables, we see that for age 34, and 10 year life insurance for female gender , there is annual premium of 6.01 per $1000 face value.
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Putting it in the above derived formula, we get:

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