the height of the pyramid is 6cm
Answer:
( 0.6 t^2 + 3t + 11 ) cm
Step-by-step explanation:
dh/dt = 1.2t + 3
at t = 0, h = 11 cm
(a)
dh / dt = 1.2 t + 3
dh = (1.2 t + 3) dt
integrate on both sides
h = 0.6 t^2 + 3t + c .... (1)
where c is the integrating constant
put t = 0
11 = c
Put in equation (1) , we get
h = ( 0.6 t^2 + 3t + 11 ) cm
Thus, teh height of tree after t years is given by
( 0.6 t^2 + 3t + 11 ) cm.
Answer:
because it can be written in the <u>form</u><u> </u>of p/q
Where p and q are integers, and q is <u>not</u> equal to zero.
