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oee [108]
3 years ago
8

to qualify as a contestant in a race, a runner has to be in the top 16% of all entrants. The running times are normally distribu

ted, with a mean of 63 min and a standard deviation of 4 min. To the nearest minute, what is the qualifying time for the race
Mathematics
1 answer:
Komok [63]3 years ago
7 0

Find P(z)=16% where z =(t-63)/4

And from the Normal Distribution tables you find that a left tail of 16% implies z=-0,9945 then:

t=-4 x 0.9945 + 63=59.22 and the solution would be 59 minutes

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