1) The measures of the opposite angles of an inscribed quadrilateral are supplementary, add up to 180.
That means that angle ROP and angle RQP are supplementary.
We can add them and set them equal to 180 so that we can solve for x first.
∠ROP + RQP = 180
x + 17 + 6x - 5 = 180
7x + 12 = 180
7x = 168
x = 24
Now use the 24 for x and solve for the measure of angle ROP.
∠ROP = x + 17
∠ROP = 24 + 17
∠ROP = 41
The answer is A
2) The answer is A.
Hope this helps :)
Answer:
93
Step-by-step explanation:
Line EJ is a straight line, with Line DC cutting through it. So 180 = Angle DCJ + Angle DCE. So Angle DCE = 48. Triangles are equal to 180°. So 180 = ? +39 +48. So ? = 93
You need to find the area of one of those bigger triangles, and one of those smaller triangles. Then multiply each area by 6 (because there are 6 sides of the big triangles, and the 6 small triangles make up the other side) and add them together. The area of a triangle is 1/2 times base times height equals area.... Equation: 1/2 (b * h) = A
The trick here is to notice that all 3 terms can be div. by 2:
2(x^2 + x - 12)
Note that -12 factors into -3 * 4 or -4 * 3. Thus,
x^2 + x - 12 = (x-4)(x+3), and so <span>2x2 + 2x − 24 = 2(x-4)(x+3).</span>
Answer:sure
Step-by-step explanation:
