All categories

3 years ago

What is the name of an investment in which deposits are made in fixed dollar amounts at regular intervals?

Mathematics

2 answers:

Anna71 [15]3 years ago

8 0

Answer: periodic investments

Step-by-step explanation:

andrew11 [14]3 years ago

4 0

Answer: periodic investment APEX

Step-by-step explanation:

You might be interested in

165% as a mixed numbers to simplest form

maksim [4K]

165% of what? If you mean 165% of 1, that's 1.65, which is 1 and 13/20

5 0

3 years ago

What is the measure of EFG? A. 88° B. 176° C. 184 D. 272°

Fudgin [204]

Cghfhgsfg sth. Dyjv

8 0

2 years ago

Which of these statements is true about adaptive evolution?

AveGali [126]

Answer:

Adaptive evolution is always changing because the environment is changing continuously.

Hence,

The right answer would be :

Adaptive evolution is a fluctuating change in a trait

Step-by-step explanation:

3 0

3 years ago

Consider the function f(x)equalscosine left parenthesis x squared right parenthesis. a. Differentiate the Taylor series about 0

dybincka [34]

I suppose you mean

$f(x)=\cos(x^2)$

Recall that

$\cos x=\displaystyle\sum_{n=0}^\infty(-1)^n\frac{x^{2n}}{(2n)!}$

which converges everywhere. Then by substitution,

$\cos(x^2)=\displaystyle\sum_{n=0}^\infty(-1)^n\frac{(x^2)^{2n}}{(2n)!}=\sum_{n=0}^\infty(-1)^n\frac{x^{4n}}{(2n)!}$

which also converges everywhere (and we can confirm this via the ratio test, for instance).

a. Differentiating the Taylor series gives

$f'(x)=\displaystyle4\sum_{n=1}^\infty(-1)^n\frac{nx^{4n-1}}{(2n)!}$

(starting at $n=1$ because the summand is 0 when $n=0$ )

b. Naturally, the differentiated series represents

$f'(x)=-2x\sin(x^2)$

To see this, recalling the series for $\sin x$ , we know

$\sin(x^2)=\displaystyle\sum_{n=0}^\infty(-1)^{n-1}\frac{x^{4n+2}}{(2n+1)!}$

Multiplying by $-2x$ gives

$-x\sin(x^2)=\displaystyle2x\sum_{n=0}^\infty(-1)^n\frac{x^{4n}}{(2n+1)!}$

and from here,

$-2x\sin(x^2)=\displaystyle 2x\sum_{n=0}^\infty(-1)^n\frac{2nx^{4n}}{(2n)(2n+1)!}$

$-2x\sin(x^2)=\displaystyle 4x\sum_{n=0}^\infty(-1)^n\frac{nx^{4n}}{(2n)!}=f'(x)$

c. This series also converges everywhere. By the ratio test, the series converges if

$\displaystyle\lim_{n\to\infty}\left|\frac{(-1)^{n+1}\frac{(n+1)x^{4(n+1)}}{(2(n+1))!}}{(-1)^n\frac{nx^{4n}}{(2n)!}}\right|=|x|\lim_{n\to\infty}\frac{\frac{n+1}{(2n+2)!}}{\frac n{(2n)!}}=|x|\lim_{n\to\infty}\frac{n+1}{n(2n+2)(2n+1)}$

The limit is 0, so any choice of $x$ satisfies the convergence condition.

3 0

3 years ago

A student wants to estimate the mean score of all college students for a particular exam. First use the range rule of thumb to m

Wewaii [24]

Answer:

See explanation below

Step-by-step explanation:

range = 2200 - 300 = 1900

To find standard deviation, we have:

standard deviation = range/4 = $\frac{1900}{4}$ = 475

The range rule of thumb estimate for the standard deviation is 475

Given:

Standard deviation, $\sigma$ = 475

Margin of Error, ME = 100

$\alpha$ = 1 - 0.90 = 0.10

Za/2 = Z0.05 = 1.64

Find sample size, n:

n ≥ $[Z_\alpha_/_2 * (\frac{\sigma}{ME})]^2$

n ≥ $[1.64 * (\frac{475}{100})]^2$

n ≥ 60.68

≈ 61

Minimun sample size,n = 61

5 0

3 years ago