The question lacks the diagram. The diagram has been attached below.
Answer:
1.
Explanation:
Exons may be defined as the coding region of the RNA whereas introns are the non coding region of the RNA. The introns must be removed out from the RNA to makes it functional molecule.
The splicing of the given molecule results in the formation of single mRNA. The 1 splicing of the introns remove intron A whereas the second splicing results in the removal of intron B. The functional mRNA consists of the mRNA with exon 1,2 and 3.
Thus, the answer is 1.
Answer:
An important feature that B-cells must have in order to become plasma cells and synthesize antibodies is increased rough endoplasmic reticulum in order to have the surface area needed for antibody production (option A).
Explanation:
The transformation of B cells into plasma cells to produce antibodies is a well known function of lymphocytes related to the immune response. This leads to a series of structural transformations in order to performs their function.
The rough endoplasmic reticulum (RER) has the function of contributing to protein synthesis, in conjunction with the ribosomes that are attached to it and the information of the mRNA.
<em>One of the changes experienced by B cells in their transition to plasma cells is the availability of larger RERs, in preparation for antibody synthesis, formed mostly by proteins</em>.
Learn more:
Plasma cells and humoral immune response brainly.com/question/1512036
Because of the moisture and height difference so some can provide more coldness while the other could be hot
Answer:
These homologous structure indicates a common ancestry
Explanation:
When 4 organisms show homologous structures, they indicates they belongs to a common ancestor from where the changes takes place in them.
The organs which are structurally dissimilar but functionally same are called as homologous organism.
Answer:
15.21 %
Explanation:
If we recall the basic formula of Hardy-Weinberg's equilibrium ; we have the following below:
p + q = 1
p² + 2pq + q² = 1
where;
p = frequency of the dominant allele in the population
q = frequency of the recessive allele in the population
p² = percentage of homozygous dominant individuals
q² = percentage of homozygous recessive individuals
2pq = percentage of heterozygous individuals
Given that p= 0.68 and q = 0.39
the percentage of the homozygous recessive genotype (q² ) will be
(0.39)² = 0.1521
= 0.1521 × 100
= 15.21 %
∴ the percentage of the population that has a homozygous recessive genotype = 15.21 %
