1 / 2 ( - 2 3x + 6x + 1)

Triangle XYZ is isosceles. The measure of the vertex angle, Y, is twice the measure of a base angle.

Alik [6]

Answer:

The answer is A, the measure of angle Z is 45°.

Step-by-step explanation: According to base angle theorem for iscoscles triangles, the base angles must be the same angle measure if the sides opposite to them are congruent. Since it is an iscoceles triangle, they are automatically congruent. This means that Y is 90 degrees. This fits into triangle sum theorem because if Z is 45 degrees, than x is also 45 degrees making a viable triangle. This means that this is the only one that actually applies. B is wrong because of triangle sum theorem, C is wrong because of triangle sum theorem, and D is wrong because of the SSS postulate and CPCTC.

5 0

3 years ago

Read 2 more answers

What is the missing length?

Angelina_Jolie [31]

3
This is because the area of a rhombus is A=sh
since the height is 4 mm, and the area is 12mm^2 the length is 3

4 0

3 years ago

Read 2 more answers

I will mark brain Can someone help me do not answer if u dont know

meriva

Answer:

1. y = 1/3x+-1

2. y = 4

Hope this helps man :D

6 0

3 years ago

Read 2 more answers

(-2x^2y^5)^3 (5x^4)/10x^7y^13

spin [16.1K]

Answer:

−4x^17y^28 is the answer i believe.

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers

A cellphone provider has the business objective of wanting to estimate the proportion of subscribers who would upgrade to a new

stiv31 [10]

Answer:

$z=\frac{0.27 -0.2}{\sqrt{\frac{0.2(1-0.2)}{500}}}=3.913$

$p_v =P(z>3.913)=0.000046$

So the p value obtained was a very low value and using the significance level given $\alpha=0.05$ we have $p_v$ so we can conclude that we have enough evidence to reject the null hypothesis, and we can said that at 5% of significance the proportion of subscribers that would upgrade to a new cellphone at a reduced cost is significantly higher than 0.2 or 20%

Step-by-step explanation:

Data given and notation

n=500 represent the random sample taken

X=135 represent the subscribers that would upgrade to a new cellphone at a reduced cost

$\hat p=\frac{135}{500}=0.27$ estimated proportion of subscribers that would upgrade to a new cellphone at a reduced cost

$p_o=0.2$ is the value that we want to test

$\alpha=0.05$ represent the significance level

Confidence=95% or 0.95

z would represent the statistic (variable of interest)

$p_v$ represent the p value (variable of interest)

Concepts and formulas to use

We need to conduct a hypothesis in order to test the claim that true proportion is higher than 0.2 or not.:

Null hypothesis: $p \leq 0.2$

Alternative hypothesis: $p > 0.2$

When we conduct a proportion test we need to use the z statistic, and the is given by:

$z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}}$ (1)

The One-Sample Proportion Test is used to assess whether a population proportion $\hat p$ is significantly different from a hypothesized value $p_o$ .

Calculate the statistic

Since we have all the info required we can replace in formula (1) like this:

$z=\frac{0.27 -0.2}{\sqrt{\frac{0.2(1-0.2)}{500}}}=3.913$

Statistical decision

It's important to refresh the p value method or p value approach . "This method is about determining "likely" or "unlikely" by determining the probability assuming the null hypothesis were true of observing a more extreme test statistic in the direction of the alternative hypothesis than the one observed". Or in other words is just a method to have an statistical decision to fail to reject or reject the null hypothesis.

The significance level provided $\alpha=0.05$ . The next step would be calculate the p value for this test.

Since is a right tailed test the p value would be:

$p_v =P(z>3.913)=0.000046$

So the p value obtained was a very low value and using the significance level given $\alpha=0.05$ we have $p_v$ so we can conclude that we have enough evidence to reject the null hypothesis, and we can said that at 5% of significance the proportion of subscribers that would upgrade to a new cellphone at a reduced cost is significantly higher than 0.2 or 20%

6 0

4 years ago

1 / 2 ( - 2 3x + 6x + 1) - 3x