All categories

3 years ago

What does 12−3/4(d+16)=−5 equal solve for d

Mathematics

1 answer:

Ratling [72]3 years ago

3 0

Answer:

d=20/3 or 6.6 repeating

Step-by-step explanation:

Let's solve your equation step-by-step.

12−

(d+16)=−5

Step 1: Simplify both sides of the equation.

12−

(d+16)=−5

12+

−3

d+−12=−5(Distribute)

(

−3

d)+(12+−12)=−5(Combine Like Terms)

−3

d=−5

−3

d=−5Step 2: Multiply both sides by 4/(-3).

(

−3

)*(

−3

d)=(

−3

)*(−5)

Answer:

You might be interested in

Here are descriptions for how two dot patterns are growing,

Arisa [49]

The steps in the patterns A and B form a sequence

The attached diagram represents dots in patterns A and B

<h3>How to draw the diagrams</h3>

For pattern A, we have:

Step 2 = 10 dots

Increment of 3 dots in each step

This means that:

Step 0 = 4 dots

Step 1 = 7 dots

Step 2 = 10 dots

Step 3 = 13 dots

For pattern A, we have the following rule

$T_n =2n^2 + 1$

When n = 0 to 3, we have:

$T_0 =2(0)^2 + 1 =1$

Step 0 = 1 dot

$T_1 =2(1)^2 + 1 =3$

Step 1 = 3 dots

$T_2 =2(2)^2 + 1 =9$

Step 2 = 9 dots

$T_3 =2(3)^2 + 1 =19$

Step 3 = 19 dots

Next, we draw the diagrams of both patterns (see attachment)

Read more about patterns at:

brainly.com/question/15590116

6 0

1 year ago

Someone please help!!!! i will mark brainliest whoever helps me!!!

vaieri [72.5K]

Answer:

in a triangle the angles have to measure to 180 degrees.

62 + 90 (right angle Q) =152

180 - 152 = 28

Angle S = 28

6 0

2 years ago

Rewrite 128 in an expomential notion using 2 as a base

KiRa [710]

$\underbrace{2\times 2\times 2\times 2\times 2\times 2 \times 2} = 128\\\\~~~~~~~~~~~~~~~~~7\\\\\\\boxed{\bf{2^7 =128}}}$

3 0

2 years ago

Need help pls!!!! Algebra

PtichkaEL [24]

Answer:

Step-by-step explanation:

6 0

2 years ago

Hi! I was wondering if you could help with this question please :)

Makovka662 [10]

Answer:

$R=\frac{QJ}{I^2t}$

Step-by-step explanation:

So we have the equation:

$Q=\frac{I^2Rt}{J}$

And we want to solve for R.

First, let's multiply both sides by J to remove the fraction on the right. So:

$(J)Q=(J)\frac{I^2Rt}{J}$

Simplify the right:

$JQ=I^2Rt$

We can rewrite our equation as:

$JQ=R(I^2t)$

So, to isolate the R variable, divide both sides by I²t:

$\frac{JQ}{I^2t}=\frac{R(I^2t)}{I^2t}$

The right side cancels, so:

$R=\frac{QJ}{I^2t}$

And we are done!

7 0

2 years ago