What is the highest common factor of 12 and 32?
It is 4, so we divide both numbers by 4.
This gives us 3 : 8. This cannot be simplified further, therefore it is the simplest form.
The answer is D.
Explanation- 28/7=4
19-4 =15
x+(x+8)+(x+100)=750
3x+108=750
3x=642
x=214
So your numbers are 214, 222 and 314
<em>Greetings from Brasil...</em>
According to the statement, one figure is scaled in relation to another, so we can apply similarity to polygons.....
So
BIG/small = BIG/small
or
small/BIG = small/BIG
12.5/10 = X/16
OR
10/12.5 = 16/X
12.5/10 = X/16
10X = 12.5 · 16
X = 200/10
<h3>X = 20</h3>
Answer:What are the equivalence classes of the equivalence relations in Exercise 3? A binary relation defined on a set S is said to be equivalence relation if it is reflexive, symmetric and transitive. An equivalence relation defined on a set S, partition the set into disjoint equivalence classes