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galben [10]
3 years ago
8

A 22 gram sample of a substance that's used to preserve fruit and vegetables has a k-value of 0.1011. Find the substance's half-

life in days. Round answer to nearest tenth.
Mathematics
1 answer:
Eddi Din [679]3 years ago
4 0
 <span>Formula for exponential decay is: 

N = No * e^-kt 

N = 1/2(45) = 22.5 

No = 45 

k = 0.1109 
The solution to your problem is as follows:

Let's try to solve the half-life if it is 45 grams, after which, you will now have an idea on how to solve the problem.

22.5 = 45 * e^(-0.1109t) 

1/2 = e^(-0.1109t) 

ln(1/2) = -0.1109t 

t = (ln(1/2))/(-0.1109) = 6.25 days


I hope my answer has come to your help. Thank you for posting your question here in Brainly. We hope to answer more of your questions and inquiries soon. Have a nice day ahead!
</span>
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Answer:

9

Step-by-step explanation:

1. First, we need to set up an equation to find the value of x and then the length of EF.

2. We know that DG is equal to 33, so we can add all the three sections it's cut into altogether to get 33. Therefore, we get an equation of: 3x - 28 + 3x - 30 + x = 33

3. (Solving for x)

Step 1: Simplify both sides of the equation.

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Step 2: Add 58 to both sides.

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Step 3: Divide both sides by 7.

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