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iragen [17]
3 years ago
11

3 exponet 8×4+9÷1×56+57

Mathematics
2 answers:
nika2105 [10]3 years ago
4 0
You would use PEMDAS

But since any number divided by 1 is the number by which it is divided by then you can eliminate that. Now your problem looks like this:
8✖️4➕9✖️56➕57

Since there are no parentheses or exponents then you would multiply.
8✖️4= 32
32➕9✖️56➕57

Then multiply the other multiplication problem.
9✖️56= 504
32➕504➕57

Now you can add all of the numbers together
32➕504=536
536➕57=593

Your answer is 593

Hope this helps! :3
stellarik [79]3 years ago
3 0

Answer:

your answer is 593

Step-by-step explanation:

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ale4655 [162]
Area of ABC : AB*AC/2

the maximum of the parabola is reached at x=-4/(2*(-1))=2 hence A is at (2,0) and B is at (2,(-2)^2+4*2+C)=(2,12+C)

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