Solve for x:<br><br> (2x-1)/3 = (x+4)/-2

Marcus needs to bike at least 80 mi this week for a training if he has already bike 25 mi this week then how many miles should h

Rashid [163]

Marcus needs to bike at least 11 miles each day.

Step-by-step explanation:

Given,

Distance to cover = 80 miles at least

Distance already biked = 25 miles

Number of days left = 5

Let,

x be the distance to cover in 5 days.

According to given statement;

Number of days left * Distance to cover + distance already bike ≥ Total distance to travel

$5x+25\geq 80\\5x+25-25\geq 80-25\\5x\geq 55$

Dividing both sides by 5

$\frac{5x}{5}\geq \frac{55}{5}\\x\geq 11$

Marcus needs to bike at least 11 miles each day.

Keywords: inequality, division

Learn more about division at:

#LearnwithBrainly

7 0

3 years ago

A box contains orange balls and green balls. The number of green balls is six more than four times the number of orange balls. I

Delvig [45]

This is your answer

3 0

2 years ago

A parabola has a minimum value of 0, a y-intercept of 4, and an axis of symmetry at x = -2

sveta [45]

Since the minimum value is 0 and axis of symmetry is -2 this means that the vertex is at -2,0 now with the y intercept of 4. You can now plug the values into Vertex form which will be y=a(x-h)^2+k. a being the shrink or stretch of the parabola, h being the x value of the vertex, and k being the y value of the vertex. with all of that plugged in it should look like y=(x+2)^2. You can check this equation by plugging in 0 as x which should find the y intercept of 4. So it should then look like y=(0+2)^2 -> y=(2)^2 -> y=4

3 0

3 years ago

Write the quadrants where the following points will lie. (a) (-20,13), (b) (-12, -8 ).

frozen [14]

Answer:

$(-20,\, 13)$ would be in the second quadrant of the cartesian plane.

$(-12,\, -8)$ would be in the third quadrant of the cartesian plane.

Step-by-step explanation:

The horizontal and vertical axes of the cartesian plane divides the plane into four quadrants. By convention, these quadrants are numbered counterclockwise starting from the quadrant on the top right:

$\begin{array}{c|c}\text{Second Quadrant} & \text{First Quadrant} \\ \cline{1-2}\\[-1em] \text{Third Quadrant} & \text{Fourth Quadrant}\end{array}$ .

Top-left: first quadrant.
Top-right: second quadrant.
Bottom-left: third quadrant.
Bottom-right: fourth quadrant.
Points on either axes (where at least one of the coordinates is $0$ ) are not in any of the four quadrants.

The $x$ -coordinate of the first point, $(-20,\, 13)$ , is $x = -20$ , which is negative. Thus, this point would be to the left of the vertical axis.

Since the $y$ -coordinate of this point, $y = 13$ , is positive, this point would be above the horizontal axis.

Thus, the point $(-20,\, 13)$ would be in the quadrant on the top-left corner of the cartesian plane. Therefore, this point would be in the second quadrant of the plane.

The second point $(-12,\, -8)$ would also be to the left of the vertical axis since the $x$ -coordinate of this point, $x = -12$ , is negative.

This point would be below the horizontal axis since the $y$ -coordinate of this point $y = -8$ is negative.

Thus, the point $(-12,\, -8)$ would be in the quadrant on the lower-left corner of the cartesian plane. This point would be thus be in the third quadrant of the plane.

4 0

3 years ago

What is 25/1000 reduced

Allushta [10]

When we are reducing we divide numerator and denomerator by the same number.
$\frac{25}{1000}= \frac{25:5}{1000:5}= \frac{5}{200}= \frac{5:5}{200:5}= \frac{1}{40}$ - its reducoed form

3 0

3 years ago

Solve for x: (2x-1)/3 = (x+4)/-2