(x - xc)² + (y - yc)² = r²
Where xc and yc are center coordinates
(x - (-4))² + (y - 3)² = 2²
x² + 2.x.4 + 4² + y² - 2.y.3 + 3² = 4
x² + 8x + 16 + y² - 6y + 9 = 4
x² + y² + 8x - 6y + 25 - 4 = 0
x² + y² + 8x - 6y + 21 = 0
PLEASE HELP
1 answer:
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In this attached picture according to the conditions of the problem we have an isosceles trapezoid and since we know that legs are equal (AD=BC=5 cm), we have to calculate bases and height in order to find the area. Working with the triangle BCD, we apply Pythagoras theorem and find that CD = = 10 cm. Since BDC is a right triangle, applying theorem for the area of triangles, we find that
and BF=
. Since ABCD is an isosceles trapezoid, triangles ADE and BFC are congruent with Angle Side Angle theorem. Then, DE=FC and with the help of Pythagoras theorem, DE=FC=2.5 cm. Then, AB=EF=5 cm and the area of the trapezoid is
