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Soloha48 [4]
3 years ago
8

PLEASE HELP

Mathematics
1 answer:
Sladkaya [172]3 years ago
3 0

Answer:

x=2

Step-by-step explanation:

3x^2=12 divide both sides by three

x^2=4 now find the square root of both sides

x=2

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I'm giving brainliest to the most helpful answer. For 50 points:
Alenkinab [10]

Answer:

1) \displaystyle\frac{5}{18}\approx27.78\%

2) \displaystyle\frac{4}{7}\approx57.14\%

3) \displaystyle  \frac{13}{16}=81.25\%

Step-by-step explanation:

We are given a two-way frequency table. Using the table, we will determine the probability for each case.

Question 1)

P(A Student With A Part Time Job Without A Car)

Using the first column, the total number of students that have a part time job is 78+30=108.

Likewise, using the first column, we can see that out of those 108 students, 30 do not have a car.

Hence, the probability that a student with a part time job without a car is:

\displaystyle P=\frac{30}{108}=\frac{5}{18}\approx27.78\%

Question 2)

P(No Car | Does Not Have A Part Time Job)

Remember that the vertical line means conditional probability.

So, we want the probability of a student having no car given that they do not have a part time job.

Using the second column, we can see that the total number of students that do not have a part time job is 18+24=42.

Likewise, using the second column, 24 do not have a car.

Hence, the probability that a student with a part time job without a car is:

\displaystyle P=\frac{24}{42}=\frac{4}{7}\approx57.14\%

Question 3)

P(Part Time Job | Car)

So, we want to probability of a student having a part time job given that they have a car.

Using the first row, the total students that have a car is 78+18=96.

And of those 96 students, 78 have a part time job.

Hence, the probability that a student with a car has a part time job is given by:

\displaystyle P=\frac{78}{96}=\frac{13}{16}=81.25\%

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3 years ago
WILL GIVE BRAINLIEST!
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Texting speed

Step-by-step explanation:

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If you work 10 hours of double time pay, and you earn $12.00 hourly, how much will you earn
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3 years ago
In a certain community, 30% of the families own a dog, and 20% of the families that own a dog also own a cat. It is also known t
Komok [63]

Answer:

What is the probability that a randomly selected family owns a cat? 34%

What is the conditional probability that a randomly selected family doesn't own a dog given that it owns a cat? 82.4%

Step-by-step explanation: We can use a Venn (attached) diagram to describe this situation:

Imagine a community of 100 families (we can assum a number, because in the end, it does not matter)

So, 30% of the families own a dog = .30*100 = 30

20% of the families that own a dog also own a cat = 0.2*30 = 6

34% of all the families own a cat = 0.34*100 = 34

Dogs and cats: 6

Only dogs: 30 - 6 = 24

Only cats: 34 - 6 = 28

Not cat and dogs: 24+6+28 = 58; 100 - 58 = 42

What is the probability that a randomly selected family owns a cat?

34/100 = 34%

What is the conditional probability that a randomly selected family doesn't own a dog given that it owns a cat?

A = doesn't own a dog

B = owns a cat

P(A|B) = P(A∩B)/P(B) = 28/34 = 82.4%

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