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3 years ago

Solve for x in the equation x - 4 = 7.A. X = -3B. x = 11C. x = 28D. x = 3

Mathematics

2 answers:

zaharov [31]3 years ago

8 0

Answer:

B) x = 11

Step-by-step explanation:

Add 4 to both sides

x - 4 + 4 = 7 + 4

x = 11

natta225 [31]3 years ago

5 0

Steps to solve:

x - 4 = 7

~Add 4 to both sides

x - 4 + 4 = 7 + 4

~Simplify

x = 11 (Option B)

Best of Luck!

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Prove the following statements: (a) For every integer x, if x is even, then for every integer y, xy is even. (b) For every integ

Murrr4er [49]

Answer and Step-by-step explanation:

(a) Given that x and y is even, we want to prove that xy is also even.

For x and y to be even, x and y have to be a multiple of 2. Let x = 2k and y = 2p where k and p are real numbers. xy = 2k x 2p = 4kp = 2(2kp). The product is a multiple of 2, this means the number is also even. Hence xy is even when x and y are even.

(b) in reality, if an odd number multiplies and odd number, the result is also an odd number. Therefore, the question is wrong. I assume they wanted to ask for the proof that the product is also odd. If that's the case, then this is the proof:

Given that x and y are odd, we want to prove that xy is odd. For x and y to be odd, they have to be multiples of 2 with 1 added to it. Therefore, suppose x = 2k + 1 and y = 2p + 1 then xy = (2k + 1)(2p + 1) = 4kp + 2k + 2p + 1 = 2(kp + k + p) + 1. Let kp + k + p = q, then we have 2q + 1 which is also odd.

(c) Given that x is odd we want to prove that 3x is also odd. Firstly, we've proven above that xy is odd if x and y are odd. 3 is an odd number and we are told that x is odd. Therefore it follows from the second proof that 3x is also odd.

3 0

3 years ago

I need help please anyone help please

steposvetlana [31]

Answer:

A. 17h+15=c

B. 4

*Steps*

83-15=68

68/17=4

2(box 1):

how to solve: 25m+200=?

m(minutes)=10

25(10)+200=450

*Give me a little to work out the other three please!*

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3 years ago

George plans to cover his circular pool for the upcoming winter season. The pool has a diameter of 20 feet and the cover extends

MariettaO [177]

For the circular cover we have:

A) The area is 379.94 ft²

B) The length of the rope must be 68.2 ft

<h3>How to get the area of the cover?</h3>

Remember that the area of a circle of radius R is given by the formula:

$A = pi*R^2$

Where pi = 3.14

In this case, the diameter of the pool is 20ft, then the radius is:

R = 20ft/2 = 10ft

And it must extend 12 inches beyond, then the radius of the cover must be:

R = 10ft + 12in

Now, we know that 1ft = 12 in, then we can rewrite the radius as:

R = 10ft +1ft = 11ft

Then the area of the cover is:

$A = 3.14*(11ft)^2 = 379.94 ft^2$

B) now we want to get the length of the rope, we know that the rope runs along the cover, then the length of the rope must be equal to the circumference of the cover.

Remember that the circumference of a circle of radius R is:

$C = 2*pi*R$