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suter [353]
3 years ago
10

15/60 as a percentage       

Mathematics
2 answers:
Goryan [66]3 years ago
7 0

Answer:

25%

Step-by-step explanation:

15 is 1/4 of 60, and 1/4 is 25%.

Ugo [173]3 years ago
3 0
15/60=1/4=0.25
0.25*100=25
15/60 in % is 25%
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a police officer records the speeds of vehicles on a road.what percent of the vehicles were traveling between 51-55 miles per ho
Marrrta [24]

Answer:

24%

Step-by-step explanation:

50 is the 100%

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12/50= 24%

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A spyware is trying to break into a system by guessing its password. It does not give up until it tries 1 million different pass
Anettt [7]

Answer:

Probability = 0.006033

Step-by-step explanation:

Given

Tries = 1000000

Required

Determine the probability of 6 different lower case letters <em>(Question continuation)</em>

<em />

There are 26 lower case letters.

The first can be any of letters 26

The second can be any of letters 26 - 1

The third can be any of letters 26 - 2

The fourth can be any of letters 26 - 3

The fifth can be any of letters 26 - 4

The sixth can be any of letters 26 - 5

Number of selection is:

Selection = 26 * (26 - 1) * (26 - 2) * (26 - 3) * (26 - 4) * (26 - 5)

Selection = 26 * 25 * 24 * 23 * 22 * 21

Selection = 165765600

The probability is:

Probability = \frac{Tries}{Selection}

Probability = \frac{1000000}{165765600}

Probability = 0.00603261472

<em></em>Probability = 0.006033<em> --- approximated</em>

6 0
2 years ago
Coach Evans recorded the height, in inches of each player on his team. The results are shown.
marysya [2.9K]

Answer:

3

Step-by-step explanation:

Given:

Team heights (inches):

61, 57, 63, 62, 60, 64, 60, 62, 63

To find: IQRs (interquartile ranges) of the heights for the team

Solution:

A quartile divides the number of terms in the data into four more or less equal parts that is quarters.

For a set of data, a number for which 25% of the data is less than that number is known as the first quartile (Q_1)

For a set of data, a number for which 75% of the data is less than that number is known as the third quartile (Q_3)

Terms in arranged in ascending order:

57,60,60,61,62,62,63,63,64

Number of terms = 9

As number of terms is odd, exclude the middle term that is 62.

Q_1 is median of terms 57,60,60,61

Number of terms (n) = 4

Median = \frac{(\frac{n}{2})^{th} +(\frac{n}{2}+1)^{th}  }{2} =\frac{2^{nd}+3^{rd}}{2} =\frac{60+60}{2}=\frac{120}{2}=60

So, Q_1=60

So, 25% of the heights of a team is less than 60 inches

Q_3 is the median of terms 62,63,63,64

Median = \frac{(\frac{n}{2})^{th} +(\frac{n}{2}+1)^{th}  }{2} =\frac{2^{nd}+3^{rd}}{2} =\frac{63+63}{2}=\frac{126}{2}=63

So, Q_3=63

So, 75% of the heights of a team is less than 63 inches

Interquartile range = Q_3-Q_1=63-60=3

The interquartile range is a measure of variability on dividing a data set into quartiles.

The interquartile range is the range of the middle 50% of the terms in the data.

So, 3 is the range of the middle 50% of the heights of the students.

4 0
3 years ago
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