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Anettt [7]
3 years ago
5

What is the solution to 2(6x+10)-3x=10-(x-2)

Mathematics
1 answer:
creativ13 [48]3 years ago
3 0

Answer:

The value of x is -4/5.

Step-by-step explanation:

First, you have to get rid of brackets, by expanding out :

2(6x+10) - 3x = 10 - (x-2)

2(6x) + 2(10) - 3x = 10 - x + 2

12x + 20 - 3x = 10 - x + 2

Next, is to bring all the x variable to one side :

12x + 20 - 3x = 10 - x + 2

12x - 3x + x = 10 + 2 - 20

10x = -8

Lastly, is to solve it by dividing 10 to both sides :

10x = -8

10x ÷ 10 = -8 ÷ 10

x = -4/5

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Need help!!!!!!! Please help solve solution!
11111nata11111 [884]

Answer:

x=65

Step-by-step explanation:

Step 1: Add -3 to both sides.

√x−1+3+−3=11+−3

√x−1=8

Step 2: Solve Square Root.

√x−1=8

x−1=82(Square both sides)

x−1=64

x−1+1=64+1(Add 1 to both sides)

x=65

Check answers. (Plug them in to make sure they work.)

x=65(Works in original equation)

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3 years ago
Is there anyone that can help me with this problem ???
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Step-by-step explanation:

5 0
3 years ago
A glass paperweight has a composite shape: a square pyramid fitting exacty on top of an 8 centimeter cube. The pyramid has a hei
ArbitrLikvidat [17]

Answer:

Part 1) The volume of the paperweight is 576\ cm^{3}

Part 2) The total surface area of the paperweight is 400\ cm^{2}

Step-by-step explanation:

Part 1) what is the volume of the paperweight?

we know that

The volume of the paperweight is equal to the volume of the square pyramid plus the volume of the cube

step 1

Find the volume of the pyramid

The volume of the pyramid is equal to

V=\frac{1}{3}BH

where

B is the area of the square base

H is the height of the pyramid

B=8^{2}=64\ cm^{2}

H=3\ cm

substitute

V=\frac{1}{3}(64)(3)=64\ cm^{3}

step 2

Find the volume of the cube

The volume of the cube is equal to

V=b^{3}

V=8^{3}=512\ cm^{3}

step 3

Find the volume of the paperweight

64\ cm^{3}+512\ cm^{3}=576\ cm^{3}

Part 2) what is the total surface area of the paperweight?​

we know that

The total surface area of the paperweight is equal to the surface area of 5 faces of the cube plus the lateral area of the pyramid

step 1

Find the surface area of 5 faces of the cube

SA=5b^{2}

SA=5(8^{2})=320\ cm^{2}

step 2

Find the lateral area of the pyramid

LA=4[\frac{1}{2}bh]

LA=4[\frac{1}{2}(8)(5)]=80\ cm^{2}

step 3

Find the total surface area of the paperweight

320\ cm^{2}+80\ cm^{2}=400\ cm^{2}

8 0
2 years ago
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