Based on the information given and the computation, the height of the goalpost will be 16.10 meters.
<h3>
Solving the equation.</h3>
Let the height of the goalpost be represented by x.
Based on the information given, the equation to solve the question will be:
1.55/1.15 = x/11.95
Cross multiply
1.55 × 11.95 = x × 1.15
x = (1.55 × 11.95) / 1.15
x = 16.10
Therefore, the height of the goalpost will be 16.10 meters.
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Answer:
The quotient is 0. 0625 and the empty boxes in remainder are 4 and 8 respectively
Step-by-step explanation:
Given: 
or 1 divided by 16
Step 1: dividend is 1 and divisor 16 it is not divisible by 16 so the Quotient is 0 remainder is 1 .
Step 2: taking the decimal point above now dividend is 10 and divisor is 16 so it is again not divisible by 16 so the quotient is 0.0 and remainder is 10 now bringing next 0 in remainder so the dividend becomes 100.
Step 3: now dividend is 100 and divisor is 16 which is divisible by 16 by 6 times which is 96 so the Quotient becomes 0.06 and remainder becomes 4 now bringing next 0 in remainder so the dividend becomes 40.
Step 4: now dividend is 40 and divisor is 16 which is divisible by 16 by 2 times which is 32 so the Quotient becomes 0.062 and remainder becomes 8 now bringing next 0 in remainder so the dividend becomes 80.
Step 5: now dividend is 80 and divisor is 16 which is divisible by 16 by 5 times which is 80 so the Quotient becomes 0.0625 and remainder becomes 0
Find, correct to the nearest degree, the three angles of the triangle with the vertices d(0,1,1), e( 2, 4,3) − , and f(1, 2, 1)
Ksju [112]
Well, here's one way to do it at least...
<span>For reference, let 'a' be the side opposite A (segment BC), 'b' be the side opposite B (segment AC) and 'c' be the side opposite C (segment AB). </span>
<span>Let P=(4,0) be the projection of B onto the x-axis. </span>
<span>Let Q=(-3,0) be the projection of C onto the x-axis. </span>
<span>Look at the angle QAC. It has tangent = 5/4 (do you see why?), so angle A is atan(5/4). </span>
<span>Likewise, angle PAB has tangent = 6/3 = 2, so angle PAB is atan(2). </span>
<span>Angle A, then, is 180 - atan(5/4) - atan(2) = 65.225. One down, two to go. </span>
<span>||b|| = sqrt(41) (use Pythagorian Theorum on triangle AQC) </span>
<span>||c|| = sqrt(45) (use Pythagorian Theorum on triangle APB) </span>
<span>Using the Law of Cosines... </span>
<span>||a||^2 = ||b||^2 + ||c||^2 - 2(||b||)(||c||)cos(A) </span>
<span>||a||^2 = 41 + 45 - 2(sqrt(41))(sqrt(45))(.4191) </span>
<span>||a||^2 = 86 - 36 </span>
<span>||a||^2 = 50 </span>
<span>||a|| = sqrt(50) </span>
<span>Now apply the Law of Sines to find the other two angles. </span>
<span>||b|| / sin(B) = ||a|| / sin(A) </span>
<span>sqrt(41) / sin(B) = sqrt(50) / .9080 </span>
<span>(.9080)sqrt(41) / sqrt(50) = sin(B) </span>
<span>.8222 = sin(B) </span>
<span>asin(.8222) = B </span>
<span>55.305 = B </span>
<span>Two down, one to go... </span>
<span>||c|| / sin(C) = ||a|| / sin(A) </span>
<span>sqrt(45) / sin(C) = sqrt(50) / .9080 </span>
<span>(.9080)sqrt(45) / sqrt(50) = sin(C) </span>
<span>.8614 = sin(C) </span>
<span>asin(.8614) = C </span>
<span>59.470 = C </span>
<span>So your three angles are: </span>
<span>A = 65.225 </span>
<span>B = 55.305 </span>
<span>C = 59.470 </span>
Well if the number is 100 dollars and it increases by four hundred percent it now costs 400 dollars. But if it was 100 dollars after the increase the original price was 25 dollars.
Answer:
f(4) = 85 1/3 or 85.333...
Step-by-step explanation:
To find f(4), you must substitute 4 in place of x whenever x appears:
f(x) = 
* 
f(4) = * 
Next, simplify the exponent:
f(4) = * 256
Finally, multiply:
f(4) = 85 1/3 or 85.333...
