1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
abruzzese [7]
3 years ago
10

Kayla knows that 1/16

Mathematics
2 answers:
Anastasy [175]3 years ago
5 0

Answer:

The quotient is 0. 0625  and the empty boxes in remainder are 4 and 8 respectively

Step-by-step explanation:

Given: \frac{1}{16} or 1 divided by 16

Step 1: dividend is 1 and divisor 16 it is not divisible by 16  so the Quotient is 0 remainder is 1 .

Step 2: taking the decimal point above now dividend is 10 and divisor is 16 so it is again not divisible by 16 so the  quotient is 0.0 and remainder is 10 now bringing next 0 in remainder so the dividend becomes 100.

Step 3: now dividend is 100 and divisor is 16 which is divisible by 16 by 6 times which is 96 so the Quotient becomes 0.06 and remainder becomes 4 now bringing next 0 in remainder so the dividend becomes 40.

Step 4: now dividend is 40 and divisor is 16 which is divisible by 16 by 2 times which is 32 so the Quotient becomes 0.062 and remainder becomes 8 now bringing next 0 in remainder so the dividend becomes 80.

Step 5: now dividend is 80 and divisor is 16 which is divisible by 16 by 5 times which is 80 so the Quotient becomes 0.0625 and remainder becomes 0

Sonja [21]3 years ago
5 0

Answer:

Step-by-step explanation:

You might be interested in
What is the volume of the composite figure. I said 36 but it is wrong.
scZoUnD [109]

Answer:

108

Step-by-step explanation:

You are correct for stating one tissue box has a volume for 36.

But notice there are 3 tissue boxes, so in order to find the total volume, you should add them up.

36+36+36=108

6 0
3 years ago
Read 2 more answers
Help pleaseee which one
MakcuM [25]
Four more I hoped this helped :)
4 0
2 years ago
Round 9.42 to one decimal place
klasskru [66]
The answer would be 9
6 0
3 years ago
Read 2 more answers
Ind the area of the rectangle, in square centimeters. Rectangle ABCD Length = 20 cm Width = 9 cm​
alexdok [17]

Answer:

180 cm^3

Step-by-step explanation:

A=lw

A=20×9

A=180

4 0
3 years ago
Help!! Which of the following best represents Z1 • Z2 select all that apply
AURORKA [14]

z_1=\sqrt{3}\left(cos\:\frac{\pi }{4}+i\:sin\:\frac{\pi }{4}\right)

z_2=\sqrt{6}\left(cos\:\frac{3\pi \:}{4}+i\:sin\:\frac{3\pi \:}{4}\right)

\cos \left(\frac{\pi }{4}\right)=\frac{\sqrt{2}}{2}

\sin \left(\frac{\pi }{4}\right)=\frac{\sqrt{2}}{2}

\cos \left(\frac{3\pi }{4}\right)=-\frac{\sqrt{2}}{2}

\sin \left(\frac{3\pi }{4}\right)=\frac{\sqrt{2}}{2}\\

Z_1*Z_2=\sqrt{3}\left(cos\:\frac{\pi }{4}+i\:sin\:\frac{\pi }{4}\right)\cdot \sqrt{6}\left(cos\:\frac{3\pi \:}{4}+i\:sin\:\frac{3\pi \:}{4}\right)

=\sqrt{3}\left(\frac{\sqrt{2}}{2}+\:i\frac{\sqrt{2}}{2}\right)\cdot \sqrt{6}\left(\frac{-\sqrt{2}}{2}+\:i\frac{\sqrt{2}}{2}\right)

On simplifying, we get

Z_1* Z_2 =-3\sqrt{2}

<h2>Therefore, correct option is  1st option.</h2>
3 0
3 years ago
Other questions:
  • I need help solving this, please!:
    14·1 answer
  • What is a unit rate????????????????????????????????????????????
    14·1 answer
  • You are having a discussion about sequences with your classmate. She insists that the sequence 2, 3, 5, 8, 12 must be either ari
    11·1 answer
  • Please answer this in two minutes
    11·1 answer
  • Alex scored 10% in his math test if the test was out of 30, what was his score
    13·2 answers
  • Whats the name of the geom<br>etric figure
    10·1 answer
  • Choose the correct product of (8x − 4)(8x + 4).
    10·2 answers
  • CNNBC recently reported that the mean annual cost of auto insurance is 965 dollars. Assume the standard deviation is 113 dollars
    15·1 answer
  • Me puedes ayudar a resolberla mas tardar a las 3:30​
    5·1 answer
  • Area of the shaded segment= <br>​
    9·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!