1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
kupik [55]
3 years ago
11

M^1/3 divided by m^1/5

Mathematics
1 answer:
alisha [4.7K]3 years ago
4 0
M^1/3 divided by m^1/5 = m^2/15<span>

m^1/5 divided by m^1/3 = 1/ </span>m^2/15<span>

m^1/3*m^1/5 = m^8/15

(m^1/3)^1/5 = m^1/15

(m^1/3m^1/5)^0 =1</span>
You might be interested in
Choose the equation that represents a line that passes through points (-1,2) and (3, 1).
Natalka [10]

Answer:

B) x + 4y = 7

Step-by-step explanation:

Hope this helps. Pls give brainliest.

5 0
3 years ago
OMG IMMA FAILLLLLLLLLLLLLLLLLL
Murrr4er [49]

Answer:

The answer is A.)10 1/2

6 0
3 years ago
Read 2 more answers
Math question. please help<br>3+2x+4x=15
Rzqust [24]

2x+4x=6x

6x+3=15

6 multiplied by 2 = 12

12 +3=15

so x =2


6 0
3 years ago
Find the area of the surface. The part of the surface z = xy that lies within the cylinder x2 + y2 = 36.
rewona [7]

Answer:

Step-by-step explanation:

From the given information:

The domain D of integration in polar coordinates can be represented by:

D = {(r,θ)| 0 ≤ r ≤ 6, 0 ≤ θ ≤ 2π) &;

The partial derivates for z = xy can be expressed  as:

y =\dfrac{\partial z}{\partial x} , x = \dfrac{\partial z}{\partial y}

Thus, the area of the surface is as follows:

\iint_D \sqrt{(\dfrac{\partial z}{\partial x})^2+ (\dfrac{\partial z}{\partial y})^2 +1 }\ dA = \iint_D \sqrt{(y)^2+(x)^2+1 } \ dA

= \iint_D \sqrt{x^2 +y^2 +1 } \ dA

= \int^{2 \pi}_{0} \int^{6}_{0} \ r  \sqrt{r^2 +1 } \ dr \ d \theta

=2 \pi \int^{6}_{0} \ r  \sqrt{r^2 +1 } \ dr

= 2 \pi \begin {bmatrix} \dfrac{1}{3}(r^2 +1) ^{^\dfrac{3}{2}} \end {bmatrix}^6_0

= 2 \pi \times \dfrac{1}{3}  \Bigg [ (37)^{3/2} - 1 \Bigg]

= \dfrac{2 \pi}{3} \Bigg [37 \sqrt{37} -1 \Bigg ]

3 0
3 years ago
For an experiment, the temperature of a liquid must stay above 60°F . The starting temperature of the liquid is 90°F . It is pla
HACTEHA [7]
The answer is <span>The liquid must be in the cooler fewer than 10 minutes.
</span>
Let:
m - the number of minutes the liquid is in the cooler.
a - the starting temperature
The function is:
f(m) = a - 3 * m     (Since the temperature decreases by 3°F each minute m, it has a negative sign)
Let:
m - <span>the number of minutes the liquid is in the cooler.
a - the starting temperature
</span>a = 90<span>°F 
</span>
<span>The temperature of a liquid must stay above 60°F:
f(m) > 60

Thus:
</span>f(m) = a - 3 * m 
f(m) > 60

a - 3 * m > 60
90 - 3m > 60
90 - 60 > 3m
30 > 3 m
30/3 > m
10 > m
Or m < 10. So the correct answer is The liquid must be in the cooler fewer than 10 minutes.
3 0
3 years ago
Other questions:
  • Maria collected r rocks.
    6·2 answers
  • A kite is a quadrilateral with two pairs of adjacent sides that are equal in length.Jackson has a rectangular piece of cloth tha
    12·1 answer
  • ******PLEASE HURRY!!!!! WILL GIVE BRAINLIEST ****************
    7·1 answer
  • Consider two​ investments, one earning simple interest and one earning compound interest. If both start with the same initial de
    8·1 answer
  • Find the equation of the given line.​
    10·1 answer
  • Write an equation in slope-intercept form of the line that passes through the points.
    6·1 answer
  • Find the mean, median, and mode(s) of the data. Do not round.<br><br> 12, 13, 40, 95, 88, 7, 95
    5·2 answers
  • Pure acid is to be added to a 10% acid solution to obtain 90L of 81% solution. What amounts of each should be used?
    5·1 answer
  • Coach Bennet’s high school basketball team has 14 players, consisting of six juniors and eight seniors. Coach Bennet must select
    15·1 answer
  • What is the value of sin © and tan o if cos © Зл and &lt;&lt; 27? 2 5
    10·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!